Line segment of length k is divided into 3 equal parts.
so first segment is 0-k/3 and third segment is 2/3k-k
so mid-pt of 1st = k/6 and 3rd = 5/6k
so the distance in between = 5/6k-k/6 = 4/6k = 2/3k
Pemdas
ok if we look at the first one
exponents first
2^3=8
2^3=8
we have
4*8/8
4*8=32
32/8=4
das is answer
the first one is the answer
Answer:
Step-by-step explanation:
Given that customers arrat a service window according to a poisson process with an average of 0.2 per minute
= 12 per hour.
a) the probability that the time between two successive arrivals is less than 6 minutes
= For one hour more than 60/6 =10 customers arrive.
P(X>10) = 0.6528
b) Prob that there will be exactly three arrivals during a given 10-minute period
P(x=3) for average 2
= 0.1804
Answer:
At least 37.74% of the procedures takes between 97.6 and 125.6 minutes
Step-by-step explanation:
The percentage is the area of the standard normal distribution curve between the values 97.6 and 125.6
The standard normal variate of the given data is found as
Thus for the given values Z is calculated as under
Similarly for the other value we have
Thus the area between the calculated values can be found from standard normal distribution table to be 37.74%
