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vaieri [72.5K]
3 years ago
8

Change y=-3x+7 to standard form

Mathematics
1 answer:
tresset_1 [31]3 years ago
3 0
Y=-3x+7 so  3x+y=7 is standard form
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(x,-2) and (-9,1);slope: -3
amid [387]

Answer:

x= -10

Step-by-step explanation:

The equation is y2-y1 over x2 over x1 so

1-(-2) over -9-(x)=3

1+2=3 over -9-(x)

3/-9-x   times -9-x  = 3  times -9-x

3=3(-9-x)

3=-27-3x

3+27=-3x

30= -3x

-10= 3x

hope it helps man!!! :)

ps may i have brainliest so i can level up

6 0
4 years ago
PLZ ANSWER ASAP!!!!! Part B
bazaltina [42]

The equation of the linear regression  is \^ y = 3.58125\^x + 202.575

<h3>Graphing tool</h3>

To determine the line of best fit, we make use of a graphing tool

See attachment for the graph of the line of best fit

<h3>The equation</h3>

From the graphing tool, we have the following calculation summary

  • Sum of X = 440
  • Sum of Y = 3601.5
  • Mean X = 44
  • Mean Y = 360.15
  • Sum of squares (SSX) = 1440
  • Sum of products (SP) = 5157

The regression Equation is then represented as:

\^y = b\^x + a

Where:

b = \frac{SP}{SSX} and a = \bar y - b \times \bar x

b = \frac{5157}{1440}

b = 3.58125

Also, we have:

a = \bar y - b \times \bar x

a= 360.15 - (3.58\times 44)

a = 202.575

So, the linear regression equation is:

\^ y = 3.58125\^x + 202.575

Read more about linear regression at:

brainly.com/question/17844286

4 0
3 years ago
Alexandra's gross annual salary is $38,556. What is the maximum amount of rent she can afford to pay? Round your answer to the n
rodikova [14]
Alexandra's gross annual salary is $38,556. The maximum amount of rent she can afford to pay can be determined by first solving for her monthly gross salary. 

Monthly Salary = ($38,556/ 12 months) = $3,213

Assuming that the amount allocated for her rent is 30% of her monthly salary, the maximum amount of rent that she can afford to pay is:

Max allowable rent = $3,213 * 0.30 = $963.90<span />
8 0
4 years ago
Read 2 more answers
Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da
miss Akunina [59]

Answer:

From the question we are told that

   The  population mean is  \mu  =  16

    The sample size is  n  =  30  

     The  sample mean is  \= x =  16.32

     The  population standard deviation is  \sigma  =  0.8

      The  level of significance is  \alpha  = 0.10

Step 1: State hypotheses:

The  null hypothesis is  H_o :  \mu = 16

The alternative hypothesis is  H_a :  \mu \ne  16

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

          t = \frac{ \= x  -\mu }{ \frac{\sigma}{ \sqrt{n} } }

=>       t = \frac{ 16.32  -16  }{ \frac{0.8 }{ \sqrt{30} } }

=>       t =2.191

Generally the degree of freedom is mathematically represented as

          df  =  n - 1

=>      df  =  30  - 1

=>      df  =29

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to  \alpha  = 0.10  is

         t = 1.311

Generally the critical regions is mathematically represented as  

         - 1.311 < T <  1.311

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so  the decision is [Reject the null hypothesis ]  

Step 5: Reach conclusions and state in English:

  There is  sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to t =2.191 at  a degree of freedom of  df  =29  is

        P( t > 2.191) =  0.0183

Generally the p-value is mathematically represented as

       p-value  = 2 * P( t >  2.191 )

=>    p-value  = 2 * 0.0183

=>    p-value  =  0.0366

Generally  looking at the value obtained we see that p- value <  \alpha hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

4 0
3 years ago
Suppose y varies jointly as × and z. What is y when × = 2 and z = 3, if y = 20 when × = 4 and z = 3?
Ne4ueva [31]

Answer:

y = kxz

Step-by-step explanation:

(Find K)

20 = k(4) (3)

20/12 = k

k = 5/3

(Find Y)

y = (5/3)(2)(3)

y = 10

I hope this helps.

7 0
2 years ago
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