It’s A i did the test myself..
Answer:
15.10 or -15.22
Step-by-step explanation:
Let's begin by listing out the information given to us:
There are four students: n = 4
Number of students to be selected: r = 2
To calculate the combination of 2 students to be chosen, we use:

Therefore, there 12 possible combinations from these
This is system of Equations.
<span>2x + 3y =10
x + y = 3
</span>
x + y = 3 (multiply this by three) to get 3x + 3y = 9
2x + 3y =10
3x + 3y = 9 Subtract them
-1x = 1
x=-1
Now plug x back into the top equation and solve for y.
I hope this helps! If not, let me know! Have a fantastical day!
It’s a! hoped this helped you!!!!