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ozzi
3 years ago
14

Need help with my geometry h/w help pls.

Mathematics
1 answer:
Stella [2.4K]3 years ago
3 0
Triangles
ABC - AB=2.5, BC=1.5, CA=2 (5: 3: 4)
ADC - AC=2, CD= 1.2, DA= 1.6
BCD - BC=1.5, BD = 0.9, DB = 1.2

Area
ABC = 1/2 *AC * CB = 1/2 *2 * 1.5 = 1.5 m^2
ADC = 1/2 *AD * DC = 1/2 * 1.6 * 1.2 = 0.96 m^2
BCD = 1/2 *BD * DC = 1/2 * 0.9 * 1.2 = 0.54 m^2

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Find the area of this figure. Round your answer to the nearest hundredth. Use 3.14 to approximate Pi.
taurus [48]

Answer:

 26.13ft^2

Step-by-step explanation:

Step  1 - As both triangles have lengths the same size, they both add together to equal a rectangle. Therefore:

4 x 3 = 12

Which is the area of the triangles.

Step 2 - Calculating the area of a circle uses the formula:

\pi r^2

Where r is the radius of the circle.

Plug the known variables in:

\pi \cdot 3^2\\\pi \cdot 9\\3.14 \cdot 9 = 28.26\\

However, this is the area of a full circle. The figure is only half a circle so we must divide this by two:

28.26 ÷ 2 = 14.13

Now, add the area of the semi-circle to the area of the triangles:

14.13 + 12 = 26.13

Therefore, the area of the figure is 26.13ft^2.

Hope this helps!

6 0
2 years ago
Find a point on the curve x^3+y^3=11xy other than the origin at which the tangent line is horizontal.
attashe74 [19]

Compute the derivative dy/dx using the power, product, and chain rules. Given

x³ + y³ = 11xy

differentiate both sides with respect to x to get

3x² + 3y² dy/dx = 11y + 11x dy/dx

Solve for dy/dx :

(3y² - 11x) dy/dx = 11y - 3x²

dy/dx = (11y - 3x²)/(3y² - 11x)

The tangent line to the curve is horizontal when the slope dy/dx = 0; this happens when

11y - 3x² = 0

or

y = 3/11 x²

(provided that 3y² - 11x ≠ 0)

Substitute y into into the original equation:

x³ + (3/11 x²)³ = 11x (3/11 x²)

x³ + (3/11)³ x⁶ = 3x³

(3/11)³ x⁶ - 2x³ = 0

x³ ((3/11)³ x³ - 2) = 0

One (actually three) of the solutions is x = 0, which corresponds to the origin (0,0). This leaves us with

(3/11)³ x³ - 2 = 0

(3/11 x)³ - 2 = 0

(3/11 x)³ = 2

3/11 x = ³√2

x = (11•³√2)/3

Solving for y gives

y = 3/11 x²

y = 3/11 ((11•³√2)/3)²

y = (11•³√4)/3

So the only other point where the tangent line is horizontal is ((11•³√2)/3, (11•³√4)/3).

3 0
2 years ago
Two workers paint lines for angled parking spaces. One worker paints a line so that m∠1=65. The other worker paints a line so th
scoundrel [369]

The image of the car park showing the 2 angles is attached.

Answer:

Their lines are parallel.

Step-by-step explanation:

From the attached image, we can see that ∠1 and ∠2 form a pair of alternate exterior angles. Thus; ∠1 = ∠2.

Now since they are congruent, it means that their lines will be parallel.

Thus, we can conclude that their lines are parallel.

3 0
3 years ago
Help?
MAXImum [283]

Answer:

$32.39

Step-by-step explanation:

She has a 15-gallon tank and it has 1/5 a tank of gas left (so about 3/15)

Because she needs to refill it and already has 1/5, she'll only need to pay for 4/5 a tank of gas (12/15).

So the equation should be 12 times $2.699.

12 × 2.699 = 32.388

Then, round to the nearest cent.

32.388 = $32.39

Hope this helped !

5 0
2 years ago
I’m confused with this question
vagabundo [1.1K]

Answer:

B and C

Step-by-step explanation:

7 0
2 years ago
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