Ask question

Ask question

All categories

3 years ago

14

Need help with my geometry h/w help pls.

1 answer:

Stella [2.4K]3 years ago

3 0

Triangles
ABC - AB=2.5, BC=1.5, CA=2 (5: 3: 4)
ADC - AC=2, CD= 1.2, DA= 1.6
BCD - BC=1.5, BD = 0.9, DB = 1.2

Area
ABC = 1/2 *AC * CB = 1/2 *2 * 1.5 = 1.5 m^2
ADC = 1/2 *AD * DC = 1/2 * 1.6 * 1.2 = 0.96 m^2
BCD = 1/2 *BD * DC = 1/2 * 0.9 * 1.2 = 0.54 m^2

You might be interested in

Find the value of x to the nearest tenth.

rosijanka [135]

Check the picture below

the angle is in degrees, thus, make sure your calculator is in Degree mode

3 0

2 years ago

Read 2 more answers

Click and drag like terms onto each other to simplify fully.<br> -24-4+7y-5+2

Jlenok [28]

Answer:

I Will Simplify Make As Brainlist

4 0

2 years ago

Justin has $5.50 more than Eva, and Emma has $7 less than Justin. Together, they have a

Dominik [7]

The answer is 48$ hope I helped you

4 0

3 years ago

Read 2 more answers

AB and BC and form a right angle at point B. If A = (-3, -1) and B = (4, 4), what is the equation of bc

adell [148]

Answer:

$y=\frac{-7}{5}x+\frac{48}{5}$ is equation of BC

Step-by-step explanation:

Given that AB and BC form a right angled triangle at point B.

i.e. BC is perpendicular to AB

Line AB contains two points (-3,-1) and (4,4)

Slope of AB = $\frac{y2-y1}{x2-x1} =\frac{4+1}{4+3} =\frac{5}{7}$

Slope of BC would be -1/slope of AB since AB and BC are perpendicular

Slope of BC =\frac{-7}{5}

Also we got a point on BC as B.

Use point slope formula

$y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}$ $y-y1=m(x-x1)\\y-4=\frac{-7}{5}(x-4)\\y=\frac{-7}{5}x+\frac{48}{5}$

6 0

3 years ago

Help? Multi-Step Equations - Fractions. Solve the Equation.<br>PLEASE DO IT STEP BY STEP (visual)

natta225 [31]

(3/4)x+(3/2)x=9/4
(3/4)x+(3.2/2.2)x=9/4
(3/4)x+(6/4)x=9/4
3x+6x=9
9x=9
x=1

8 0

2 years ago

Read 2 more answers