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earnstyle [38]
3 years ago
12

A student has gotten the following grades on his tests: 87, 95, 76, and 88. He wants an 85 or better overall. What is the minimu

m grade he must get on the last test in order to achieve that average? ​
Mathematics
1 answer:
Hoochie [10]3 years ago
4 0

Answer:

He must get at least a 90 in order to recieve an 85 percent or higher

Step-by-step explanation:

You might be interested in
∠A and \angle B∠B are supplementary angles. If m\angle A=(2x-16)^{\circ}∠A=(2x−16) ∘ and m\angle B=(5x+28)^{\circ}∠B=(5x+28) ∘ ,
Otrada [13]

Answer:

The measure of angle A is 32

Step-by-step explanation:

A+B=180

2x-16+5x+28=180

7x+12=180

7x=168

x=24

A=2(24)-16

A=48-16

A=32

6 0
3 years ago
How do i solve for x if 6x - 6 - 7x =6
Dmitry_Shevchenko [17]

Answer:

X = 12

Step-by-step explanation:

Step  1  :

Pulling out like terms :

1.1     Pull out like factors :

  -x - 12  =   -1 • (x + 12)

Equation at the end of step  1  :

Step  2  :

Solving a Single Variable Equation :

2.1      Solve  :    -x-12 = 0

Add  12  to both sides of the equation :

                     -x = 12

Please said thanks

7 0
3 years ago
Read 2 more answers
How much material is needed to construct a triangular tent that is 6 feet wide 4 feet tall and 8 feet long with side measurement
jonny [76]

Answer: 152ft^2

The amount of material needed to construct the tent is 152ft^2

Step-by-step explanation:

The amount of material needed to construct a triangular tent= the surface area of the triangular tent.

S.A = area of the 2 side rectangles + area of the 2 side triangles + area of the base.

S.A = Ab + At + Ar ....1

Area of the base Ab= Length × width = 8×6 = 48ft^2

Area of the two triangles At = 2 × 0.5 × width × height

At = width × height = 6×4 = 24ft^2

Area of the two rectangles Ar = 2 × side measurement × length

Side measurement is given as 5ft.

or it can be calculated using;

Side length can be calculated using Pythagoras theorem.

Examining the figure attached, we can see that;

Side breadth b = √(h^2 + (w/2)^2)

b = √(4^2 + (6/2)^2) = √(16+9) = √25

b = 5ft

Ar = 2×5×8 = 80ft^2

From eqn1, S.A can be solved as;

S.A = 48 + 24 + 80

S.A = 152ft^2

7 0
3 years ago
Find the area of a parallelogram with these dimensions.
aev [14]
The area is 14! hope this helps
3 0
3 years ago
PLEASE HELP ASAP WILL GIVE BRAINLEST
Fittoniya [83]
Each ratio is
3:1
3:1
3:1
3:1
7 0
3 years ago
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