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3 years ago

12

A student has gotten the following grades on his tests: 87, 95, 76, and 88. He wants an 85 or better overall. What is the minimu

m grade he must get on the last test in order to achieve that average?

1 answer:

Hoochie [10]3 years ago

4 0

Answer:

He must get at least a 90 in order to recieve an 85 percent or higher

Step-by-step explanation:

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5 is what percent of 20

Alenkasestr [34]

It is one fourth of twenty so therefor 5 is 25% of 20

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plz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help i need helpplz help

Volgvan

Answer:

the answer should be 9

Step-by-step explanation:

$(256 * 3^{-5} * 6^{0} )^{-2} * (\frac{3^{-2}}{2^{3}} )^{4} * 2^{28}$

$(256*\frac{1}{3^{5}} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(256*\frac{1}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{256}{243} *6^{0})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{256}{243})^{-2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$(\frac{243}{256})^{2}*(\frac{3^{-2}}{2^{3}})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{2^{3}*3^{2}})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{8*9})^{4}*2^{28}$

$\frac{59049}{65536}*(\frac{1}{72})^{4}*2^{28}$

$\frac{59049}{65536}*\frac{1}{26873856}*2^{28}$

$\frac{9}{65536}*\frac{1}{4096}*2^{28}$

$\frac{9}{65536*4096}*2^{28}$

$\frac{9}{268435456}*268435456$

$9$

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3 years ago

Read 2 more answers

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Step-by-step explanation:

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