Answer:
The empirical formula is C3H4O4
Explanation:
Step 1: Data given
Suppose we have 100 grams of malonic acid
Malonic acid contains:
34.63 % C = 34.63 grams C
3.87 % H = 3.87 grams H
61.50 % O = 61.50 grams O
Molar mass of C = 12.01 g/mol
Molar mass of H = 1.01 g/mol
Molar mass of O = 16.00 g/mol
Step 2: Calculate moles
Moles = mass / molar mass
Moles C = 34.63 grams / 12.01 g/mol
Moles C = 2.883 moles
Moles H = 3.87 grams / 1.01 g/mol
Moles H = 3.83 moles
Moles O = 61.50 grams / 16.00 g/mol
Moles O = 3.844 moles
Step 3: Calculate mol ratio
We divide by the smallest amount of moles
C: 2.883 / 2.883 = 1
H: 3.83/ 2.883 = 1.33
O: 3.844 / 2.883 = 1.33
The empirical formula is C3H4O4
An organ in the human or animal body that secretes particular chemical substances for use in the body or for discharge into the surroundings.
Explanation:
Gamma rays are the electromagnetic waves that have the highest frequency and the lowest wavelength compared to all other electromagnetic waves.
f = 300 EHz
In terms of frequency the order of frequency is
Gamma rays > X rays > Ultraviolet > Visible > Infrared > high frequency > low frequency > Extremely low frequency
In terms of wavelength the order is the opposite of the frequency
Gamma rays < X rays < Ultraviolet < Visible < Infrared < high frequency < low frequency < Extremely low frequency
Answer:
Molarity of the solution = 3.000 M
Volume of the solution = 250.0 mL = 0.25 L
moles in 250.0 mL = molarity x volume of the solution
= 3.000 M x 0.25 L
= 0.75 mol
Hence, 0.75 mol of NaCl is needed to prepare 250.0 mL of 3.000 M NaCl solution.
Moles (mol) = mass (g) / molar mass (g/mol)
Moles of NaCl in 250.0 mL = 0.75 mol
Molar mass of NaCl = 58.44 g/mol
Mass of NaCl in 250.0 mL = Moles x Molar mass
= 0.75 mol x 58.44 g/mol
= 43.83 g
Hence, 43.83 g of NaCl is needed to prepare 250.0 mL of 3.000 M solution.
Explanation:
