Answer:

Explanation:
Hello!
In this case, since the reactions between NaOH and the acids are:

Whereas we can see the 1:1 and 2:1 mole ratios between NaOH and HCl and H2SO4 respectively. In such a way, at the equivalence point we realize that:

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Answer:- 0.134 seconds
Solution:- The speed is given as
and the circumference is 24900 miles which is same as the distance light have to covered. It asks to calculate the time required to cover this distance by the light.
We need to do unit conversion from miles to meter as the speed is given in meter per second.
1 mile = 1609.34 meter
So, 
= 40072566 meters
Know that, 
It's rearranged to time as, 
Let's plug in the values in it:

= 0.134 seconds
So, the light would take 0.134 seconds to travel the mentioned speed. The answer without the unit is 0.134.
Define stoichiometry and explain why it is such a useful tool for chemists. ...Explain<span> what a limiting reactant is and why it is important in </span>stoichiometry<span>. A limiting reactant is the reactant in a chemical equation that runs out first. It is important because its quantity determines the amount of products produce</span>
About 100,000 light years
Answer: 0.25 mole PH3
Explanation: 1 mole of PH3 is equal to its molar mass P= 31 , H 1x3 = 34g
Solution:
8.5 g PH3 x 1 mole PH3 / 34 g PH3
= 0.25 mole PH3