The fact that the four new elements are Period 7 of the table means that they all

Assuming the substance is one of those listed in the table presented in this lesson, what is the identity of the substance?

zepelin [54]

The identity of the substance is Iron.

<h3>Properties of Iron</h3><h3>Chemical properties</h3>

The element iron has the atomic number 26 and the symbol Fe
Electronic configuration of Fe is [AR] 3d6 4s2
The atomic weight of Iron is 55.847
The element iron belong to the group VIII of the periodic table

It is the fourth most prevalent element in the crust of the world
It is a highly reactive element as it gets rusted readily in the moisture of air

<h3>Physical properties</h3>

It is a heavy metal in the first transition series
The color of iron is silvery grey
High malleability and ductility
It has a strong electrical conductivity.

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8 0

2 years ago

Read 2 more answers

What most likely happens during this reaction

Bad White [126]

Answer:

I think that it is A I am sorry if I am wrong

Explanation:

8 0

3 years ago

Molybdenum (Mo) has a body centered cubic unit cell. The density of Mo is 10.28 g/cm3. Determine (a) the edge length of the unit

ser-zykov [4K]

<u>Answer:</u>

<u>For a:</u> The edge length of the unit cell is 314 pm

<u>For b:</u> The radius of the molybdenum atom is 135.9 pm

<u>Explanation:</u>

<u>For a:</u>

To calculate the edge length for given density of metal, we use the equation:

$\rho=\frac{Z\times M}{N_{A}\times a^{3}}$

where,

$\rho$ = density = $10.28g/cm^3$

Z = number of atom in unit cell = 2 (BCC)

M = atomic mass of metal (molybdenum) = 95.94 g/mol

$N_{A}$ = Avogadro's number = $6.022\times 10^{23}$

a = edge length of unit cell =?

Putting values in above equation, we get:

$10.28=\frac{2\times 95.94}{6.022\times 10^{23}\times (a)^3}\\\\a^3=\frac{2\times 95.94}{6.022\times 10^{23}\times 10.28}=3.099\times 10^{-23}\\\\a=\sqrt[3]{3.099\times 10^{-23}}=3.14\times 10^{-8}cm=314pm$

Conversion factor used: $1cm=10^{10}pm$

Hence, the edge length of the unit cell is 314 pm

<u>For b:</u>

To calculate the edge length, we use the relation between the radius and edge length for BCC lattice:

$R=\frac{\sqrt{3}a}{4}$

where,

R = radius of the lattice = ?

a = edge length = 314 pm

Putting values in above equation, we get:

$R=\frac{\sqrt{3}\times 314}{4}=135.9pm$

Hence, the radius of the molybdenum atom is 135.9 pm

4 0

3 years ago

Guillaume Amontons first took a stab at measuring absolute zero in 1702. What would be the most reasonable way it would have bee

Tema [17]

The most reasonable way to measure absolute zero would have been to extrapolate the ideal gas law.

<h3>What is Absolute zero?</h3>

This is referred to the temperature at which a thermodynamic system has the lowest form of energy.

Guillaume Amontons used gas equation to prove that absence of heat was theoretically possible which would have involved only extrapolating the ideal gas law.

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3 0

2 years ago

If we have 0.06 moles of HCI <br><br> How many grams of magnesium metal is that?

vesna_86 [32]

Answer:

1.44 g

Explanation:

From the question given above, the following data were obtained:

Number of mole of HCl = 0.06 mole

Mass of Mg =?

From the question given above, we discovered the number of mole of HCl is equivalent to the number of mole of Mg. Thus,

Number of mole of Mg = number of mole of HCl

Number of mole of Mg = 0.06 mole

Finally, we shall determine the mass of Mg. This can be obtained as follow:

Number of mole of Mg = 0.06 mole

Molar mass of Mg = 24 g/mol

Mass of Mg =?

Mass = mole × molar mass

Mass of Mg = 0.06 × 24

Mass of Mg = 1.44 g

Therefore, the mass of magnesium is 1.44 g

4 0

3 years ago