Explanation:
a) Cr is <u>acid</u> K is <u>base</u>
b) Ca is <u>base</u> and the other left part is <u>acid</u>
c)Ca is <u>base</u> and F2 is <u>acid</u>
<u>d</u><u>)</u><u> </u>NH4 is <u>acid</u> and SO4 is <u>base</u>
Answer:
Explanation:
The atomic number tell us the number of protons and neutrons in the nucleus of an atom. in other words ,each element has a unique number that identifies how many protons are in one atom of that element example, all hydrogen atoms, and only hydrogen atoms, contain one proton and have an atomic number of 1.
Answer:
a) Neutralisation
b) Combustion
c) Synthesis
d) Decomposition
e) Neutralisation
f) Double Displacement Reaction
h) Single Displacement Reaction
i) Double Displacement Reaction
j) Combustion
Explanation:
Synthesis is a reaction where various compounds/ elements react to form a totally new compound.
Decomposition is a reaction where a single compound breaks down into several components due to excessive heating or energy applied.
Single Displacement Reaction is a type of chemical reaction where an element reacts with a compound and takes the place of another element in that compound.
Double Displacement Reaction is a type of chemical reaction where two compounds react, and the positive ions (cation) and the negative ions (anion) of the two reactants switch places, forming two new compounds or products.
Combustion is a reaction where a compound/ element oxidises in the presence of Oxygen.
Neutralisation reaction is a reaction where an acid reacts with a base to form a salt.
Answer:
10 molecules of NH₃.
Explanation:
N₂ + 3H₂ --> 2NH₃
As the N₂ supply is unlimited, what we need to do to solve this problem is <u>convert molecules of H₂ into molecules of NH₃</u>. To do so we use the <em>stoichiometric coefficients</em> of the balanced reaction:
- 15 molecules H₂ *
= 10 molecules NH₃
10 NH₃ molecules could be prepared from 15 molecules of H₂ and unlimited N₂.
Answer:
See Explanation
Explanation:
The equation of the reaction;
KHSO4(aq) + KOH(aq) -------> K2SO4(aq) + H2O(l)
Number of moles of KHSO4 = 49.6 g/136.169 g/mol = 0.36 moles
Since the reaction is in a mole ratio of 1:1, 0.36 moles of K2SO4 is produced.
Number of moles of KOH = 25.3 g/56.1056 g/mol = 0.45 moles
Since the reaction is 1:1, 0.45 moles of K2SO4 is produced
Hence K2SO4 is the limiting reactant.
Mass of K2SO4 formed = 0.36 moles of K2SO4 * 174.26 g/mol = 62.7 g
So;
1 mole of KHSO4 reacts with 1 mole of KOH
0.36 moles of KHSO4 reacts with 0.36 * 1/1 = 0.36 moles of KOH
Amount of excess KOH = 0.45 moles - 0.36 moles = 0.09 moles
Mass of excess KOH = 0.09 moles * 56.1056 g/mol = 5 g of excess KOH
