Answer:
The confidence interval for the population variance of the thicknesses of all aluminum sheets in this factory is Lower limit = 2.30, Upper limit = 4.83.
Step-by-step explanation:
The confidence interval for population variance is given as below:
![[(n - 1)\times S^{2} / X^{2} \alpha/2, n-1 ] < \alpha < [(n- 1)\times S^{2} / X^{2} 1- \alpha/2, n- 1 ]](https://tex.z-dn.net/?f=%5B%28n%20-%201%29%5Ctimes%20S%5E%7B2%7D%20%20%2F%20%20X%5E%7B2%7D%20%20%5Calpha%2F2%2C%20n-1%20%5D%20%3C%20%5Calpha%20%3C%20%5B%28n-%201%29%5Ctimes%20S%5E%7B2%7D%20%20%2F%20X%5E%7B2%7D%201-%20%5Calpha%2F2%2C%20n-%201%20%5D)
We are given
Confidence level = 98%
Sample size = n = 81
Degrees of freedom = n – 1 = 80
Sample Variance = S^2 = 3.23
![X^{2}_{[\alpha/2, n - 1]} = 112.3288\\\X^{2} _{1 -\alpha/2,n- 1} = 53.5401](https://tex.z-dn.net/?f=X%5E%7B2%7D_%7B%5B%5Calpha%2F2%2C%20n%20-%201%5D%7D%20%20%20%3D%20112.3288%5C%5C%5CX%5E%7B2%7D%20_%7B1%20-%5Calpha%2F2%2Cn-%201%7D%20%3D%2053.5401)
(By using chi-square table)
[(n – 1)*S^2 / X^2 α/2, n– 1 ] < σ^2 < [(n – 1)*S^2 / X^2 1 -α/2, n– 1 ]
[(81 – 1)* 3.23 / 112.3288] < σ^2 < [(81 – 1)* 3.23/ 53.5401]
2.3004 < σ^2 < 4.8263
Lower limit = 2.30
Upper limit = 4.83.
The answer is: " 60° " .
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" m∠A = 60° " .
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Explanation:
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Note: All triangles, by definition, have 3 (three) sides and 3 (three angles).
The triangle shown (in the "image attached") has three EQUAL side lengths. Therefore, the triangle shown is an "equilateral triangle" and has 3 (three) equal angles, as well.
All triangles by, definition, have 3 (three) angles that add up to "180° " .
Since each of the 3 (three) angles is equal; and the three angles are:
"∠A" , "∠B" , and "∠C" ;
We can find the measure of "∠A" ; denoted as: "m∠A" ; as follows:
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m∠A = 180° ÷ 3 = 60° .
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The answer is: " 60° " .
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m∠A = " 60° " .
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Answer:
6
Step-by-step explanation:
Step 1:
16 = 4 + 2x
Step 2:
12 = 2x
Answer:
6 = x
Hope This Helps :)
Answer:
d=1/2
b=1/25
b(row 2)=1/5
e=7/100
explanation: think about them as numbers out of 100 then simplify :)
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