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Lena [83]
3 years ago
10

Which pair of angles must be supplementary?

Mathematics
2 answers:
Anton [14]3 years ago
7 0

Answer:

1 and 6

Step-by-step explanation:

mr Goodwill [35]3 years ago
6 0

Answer:

I think 2 and 5

Step-by-step explanation:

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Consider a point, N, located at (6, 8). Name the
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(6,2)
(-2,8)
(14,8)
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The graph shows a nonlinear function. This is because the line is not straight. I hope this helps :) <span />
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Please help! asap! thank you so much! I have photos attached!
schepotkina [342]

Answer:


Step-by-step explanation:

Given problems are absolute value problems, So we need to plug the values of given parameters and get the final result.

We have given here,

a =-2 , b = 3 ,  c = -4 and d = -6

Now we know that An absolute function always gives a positive value.

Let's apply this strategy in the given problems.

1. ║a+b║

Plug a= -2 and b = 3

We get, ║-2+3║=║1║= 1

2. 5║c+b║

Plug c= -4 and b=3

i.e.   5║-4 + 3║= 5║-1║=5×1 = 5

3. a+b║c║

Plug values a= -2 , b=3 and c=-4

i.e -2 +3║-4║ = -2 + 3×4 = -2 + 12 = 10

4. ║a+c║÷(-d)

i.e ║-2 + (-4)║÷(-6) = ║-6║÷(-6) = 6÷(-6) = -1

5. 3║a+d║+b

i.e 3║-2+(-6)║+3 = 3║-8║+3 = 3×8 +3 = 27

4 0
3 years ago
Directions : Factor each of the following Differences of two squares and write your answer together with solution​
N76 [4]

\huge \boxed{\mathfrak{Question} \downarrow}

Factor each of the following differences of two squares and write your answer together with solution.

\large \boxed{\mathbb{ANSWER\: WITH\: EXPLANATION} \downarrow}

<h3><u>1. x² - 36</u></h3>

\sf \: x ^ { 2 } - 36

Rewrite \sf\:x^{2}-36 as x^{2}-6^{2}. The difference of squares can be factored using the rule:\sf\: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\boxed{ \boxed{ \bf\left(x-6\right)\left(x+6\right) }}

__________________

<h3><u>2. 49 - x²</u></h3>

\sf \: 49 - x ^ { 2 }

Rewrite 49-x² as 7²-x². The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\sf \: \left(7-x\right)\left(7+x\right)

Reorder the terms.

\boxed{ \boxed{ \bf\left(-x+7\right)\left(x+7\right) }}

__________________

<h3><u>3. 81 - c²</u></h3>

\sf \: 81 - c ^ { 2 }

Rewrite 81-c²as 9²-c². The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\sf\left(9-c\right)\left(9+c\right)

Reorder the terms.

\boxed{ \boxed{ \bf\left(-c+9\right)\left(c+9\right) }}

__________________

<h3><u>4</u><u>.</u><u> </u><u>m²</u><u>n</u><u>²</u><u> </u><u>-</u><u> </u><u>1</u></h3>

\sf \: m ^ { 2 } n ^ { 2 } - 1

Rewrite m²n² - 1 as \sf\left(mn\right)^{2}-1^{2}. The difference of squares can be factored using the rule: \sf\:a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).

\boxed{ \boxed{ \bf\left(mn-1\right)\left(mn+1\right) }}

4 0
3 years ago
Read 2 more answers
5(y-4)=7(2y+1)<br>I need the answer​
8_murik_8 [283]

Answer: y = -3

Move all terms containing y to the left, all other terms to the right

<u>Add -14y to each side of the equation</u>

<u></u>-20 + 5y + -14y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 5y + -14y = -9y </u>

<u></u>-20 + -9y = 7 + 14y + -14y<u></u>

<u></u>

<u>Combine like terms: 14y + -14y = 0 </u>

<u></u>-20 + -9y = 7 + 0\\-20 + -9y = 7<u></u>

<u></u>

<u>Add '20' to each side of the equation</u>

<u></u>-20 + 20 + -9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: -20 + 20 = 0 </u>

<u></u>0 + -9y = 7 + 20\\-9y = 7 + 20<u></u>

<u></u>

<u>Combine like terms: 7 + 20 = 27 </u>

<u></u>-9y = 27<u></u>

<u></u>

<u>Divide each side by -9</u>

<u></u>-9y/9=27/-9\\y=-3<u></u>

8 0
3 years ago
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