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3 years ago

I been so lost and confused on this ;( help?

Mathematics

1 answer:

viva [34]3 years ago

5 0

2x - 5y = 9
2x -9 = 5y
(2x -9) /5 = y

x= -1
(2(-1) -9)/5 =y
(-2 -9) / 5 = y
-11/5 = y

x=0
(0-9)/5 = y
-9/5 = y

x=1
(2(1) - 9) /5 = y
-7/5 = y

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2/5 × 6/7= simplify form

kirill115 [55]

Answer:

2 x 6 = 12

5 x 7 = 35

12/35

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Penelope made note of all the bicycles and cars she could see parked or locked on acertain city block. All the cars had exactly

lesantik [10]

Given:

The number of cycles is, n (s) = 7.

The number of wheels in the cycle is, n (sw) = 2.

The number of cars is, n (c) = 15.

The number of wheels in the car is, n (cw) = 4.

The obective is to find the total number of wheels.

The total number of wheels is,

$\begin{gathered} T=n(sw)\cdot n(s)+n(cw)\cdot n(c) \\ =2\cdot7+4\cdot15 \\ =14+60 \\ =74\text{ whe}els \end{gathered}$

Hence, there are 74 wheels in the block.

If there are x bicycles and y cars, the equatioin will be,

$\begin{gathered} T=n(sw)\cdot x+n(ce)\cdot15 \\ T=2x+4x \end{gathered}$

Hence, the number of wheels for x bicycles and y cars is 2x+4x.

6 0

1 year ago

in 2010, sarah spent $500 buying clothes. In 2013, she spent $350 buying clothes. What was the rate change from 2010 to 2013?

Yuki888 [10]

Answer:

150

Step-by-step explanation

because 500 minus 350 is 150

5 0

3 years ago

Find the range of the graphed function.

rusak2 [61]

Range is set of all y-values. To find a range of graphed function, we need to know that range starts from the minimum value of graph to maximum value. That's because the minimum value is the least value that you can get by substituting the domain and the maximum value is the largest value that you can get by substituting the domain as well.

Now we don't talk about domain here, we talk about range. See the attachment! You are supposed to focus on y-axis, plane or vertical line. See how the minimum value of function is the negative value while the maximum value is positive.

That means any ranges that don't contain the negative values are cleared out. (Hence A and C choices are wrong.)

Next, range being set of all real numbers mean that graphed functions don't have maximum value or minimum value (We can say that both max and min are infinite.)

Take a look at line graph as an example of range being set of all real numbers, or cubic function.

Answer/Conclusion

The range exists from negative value which is -9 to the maximum value which is 5.
That means the range is -9<=y<=5

3 0

3 years ago

8/x-5 - 9/x-4 = 5/x^2-9x+20

adelina 88 [10]

If you're using the app, try seeing this answer through your browser: brainly.com/question/2752942

_______________

Solve the equation:

$\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}$

Reduce the fractions at the left side so that they have the same denominator:

$\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}$

Numerators must be equal:

$\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}$

I hope this helps. =)

Tags: rational equation fraction solution algebra

7 0

3 years ago