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bagirrra123 [75]
3 years ago
8

I been so lost and confused on this ;( help?

Mathematics
1 answer:
viva [34]3 years ago
5 0
2x - 5y = 9
2x -9 = 5y
(2x -9) /5 = y

x= -1
(2(-1) -9)/5 =y
(-2 -9) / 5 = y
-11/5 = y

x=0
(0-9)/5 = y
-9/5 = y

x=1
(2(1) - 9) /5 = y
-7/5 = y
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∫∫x²(y-x)dxdy ,d là miền giới hạn bởi các đường y=x² và x=y²
Valentin [98]

It looks like the integral is

\displaystyle \iint_D x^2 (y-x) \,\mathrm dx\,\mathrm dy

where <em>D</em> is the set

<em>D</em> = {(<em>x</em>, <em>y</em>) : 0 ≤ <em>x</em> ≤ 1 and <em>x</em> ² ≤ <em>y</em> ≤ √<em>x</em>}

So we have

\displaystyle \iint_D x^2(y-x)\,\mathrm dx\,\mathrm dy = \int_0^1 \int_{x^2}^{\sqrt x} x^2(y-x)\,\mathrm dy\,\mathrm dx \\\\ = \int_0^1 \left(\frac{x^2y^2}2-x^3y\right)\bigg|_{y=x^2}^{y=\sqrt x} \\\\ = \int_0^1 \left(\frac{x^3}2-x^{7/2}+x^5-\frac{x^6}2\right)\,\mathrm dx \\\\ = \left(\frac{x^4}8 - \frac{2x^{9/2}}9 + \frac{x^6}6 - \frac{x^7}{14}\right)\bigg|_{x=0}^{x=1} = \frac18-\frac29+\frac16-\frac1{14} = \boxed{-\frac{1}{504}}

5 0
3 years ago
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8 0
4 years ago
12. Make a box-and-whisker plot of the data. (1 point)
Sophie [7]

The box-and-whisker plot of the data, showing the five-number summary, is shown in the image atatched below.

<h3>What is the Box-and-whisker Plot?</h3>

The box-and-whisker plot is a plot that displays the minimum, maximum, median, lower and upper quartile of a data, which is termed as the five-number summary of a data.

Given the data, 20, 23, 28, 14, 13, 24, 18, 11, find the five-number summary:

  • Minimum - 11
  • Lower Quartile - 13.5
  • Median - 19
  • Upper Qaurtile - 23.5
  • Maximum - 28

Therefore, the box-and-whisker plot of the data, showing the five-number summary, is shown in the image atatched below.

Learn more about box-and-whisker ploton:

brainly.com/question/12343132

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