An ode is a type of lyrical stanza. It is an elaborately structured poem praising or glorifying an event or individual, describing nature intellectually as nicely as emotionally. A basic ode is structured in three major parts: the strophe, the antistrophe, and the epode.
F(x) = x^2 + 1
f(4) = 4^2 + 1 = 16 + 1 = 17
2*f(4) = 2 * 16 = 32
KE = 1/2(m * v^2)
KE = 1/2(1350 * 12^2)
KE = 1/2(1350 * 144)
KE = 1/2(194,400)
KE = 97,200 Joules
Answer:
45,000
Step-by-step explanation:
You should divide 20 by 600 to see how many miles he would run per mile
and you take 30 x 1,500 to get your answer
According to the equation located here: https://www.1728.org/glwarmng.htm burning one gallon of gasoline produces 19.3 pounds of carbon dioxide.
So, if a car gets 37 miles per gallon and if it travels 400 miles, it will use 10.81 gallons of gasoline and will produce 19.3 * 10.81 = 208.63 pounds of carbon dioxide.
