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Nadya [2.5K]
4 years ago
7

Write g(x)=4x^2+88 in vertex form

Mathematics
1 answer:
umka21 [38]4 years ago
5 0

Answer:

y

=

4

(

x

+

11

)

2

−

484

Step-by-step explanation:

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Complete the number sentence to show the distributive property 7X6=
Firlakuza [10]
6x7
(6x5=)+(6x2=)
30 + 12
42
7 0
4 years ago
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Write the expression as the sine, cosine, or tangent of an angle. (6 points) cos 94° cos 37° + sin 94° sin 37°
klasskru [66]

Answer:

cos57 = 0.5446

sin57 = 0.8387

tan57 = 1.5399

Step-by-step explanation:

Given

cos 94\° cos 37\° + sin 94\° sin 37\°

Required

Determine the

<em>- sin</em>

<em>- cosine</em>

<em>- tangent</em>

of an angle

The given expression can be represented as follows;

cosAcosB + sinAsinB

Where A = 94 and B = 37

In trigonometry:

cosAcosB + sinAsinB = cos(A - B)

Substitute 94 for A and 37 for B

cos(A - B) = cos(94 - 37)

cos(A - B) = cos(57)

Hence, the angle is 57;

<em>Since 57 is not a special angle; I'll solve using a calculator</em>

cos57 = 0.5446

sin57 = 0.8387

tan57 = 1.5399

4 0
3 years ago
Read 2 more answers
A particular fruit's weights are normally distributed, with a mean of 446 grams and a standard deviation of 17 grams. If a fruit
LekaFEV [45]

Answer:

The weight corresponding to which weight will be larger than 14% of times equals 427.635 grams.

Step-by-step explanation:

We need to find the value of weight that corresponds to 14% of area under the normal distribution curve

It is given that

\overline{X}=446\\\\\sigma =17

Using standard normal distribution tables we find value of Z corresponding to 14% of the area as -1.080

Thus using the standard equation

Z=\frac{X-\overline{X}}{\sigma }\\\\X=\sigma \times Z+\overline{X}\\\\\therefore X=427.635grams

4 0
3 years ago
Read 2 more answers
Cindy asked to borrow Melinda's math book. Which sentence shows a correctly written response to Cindy's question?​
Amiraneli [1.4K]

Answer:

C

Step-by-step explanation:

8 0
4 years ago
A simple random sample of size nequals=8181 is obtained from a population with mu equals 77μ=77 and sigma equals 27σ=27. ​(a) De
ivanzaharov [21]

Answer:

a) P(\bar X>81.5)=1-0.933=0.067

b) P(\bar X

c) P(73.4  

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Let X the random variable that represent interest on this case, and for this case we know the distribution for X is given by:

X \sim N(\mu=77,\sigma=27)  

And let \bar X represent the sample mean, the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

On this case  \bar X \sim N(77,\frac{27}{\sqrt{81}})

Part a

We want this probability:

P(\bar X>81.5)=1-P(\bar X

The best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}

If we apply this formula to our probability we got this:

P(\bar X >81.5)=1-P(Z

P(\bar X>81.5)=1-0.933=0.067

Part b

We want this probability:

P(\bar X\leq 69.5)

If we apply the formula for the z score to our probability we got this:

P(\bar X \leq 69.5)=P(Z\leq \frac{69.5-77}{\frac{27}{\sqrt{81}}})=P(Z

P(\bar X\leq 69.5)=0.0062

Part c

We are interested on this probability

P(73.4  

If we apply the Z score formula to our probability we got this:

P(73.4

=P(\frac{73.4-77}{\frac{27}{\sqrt{81}}}

And we can find this probability on this way:

P(-1.2

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.  

P(-1.2

3 0
4 years ago
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