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GenaCL600 [577]
3 years ago
5

Need help with this question

Mathematics
1 answer:
Mashcka [7]3 years ago
6 0
For this question, you would want to set up a system of equations. 

Let x = Dog Food
Let y = Cat Food

5x+2y=20
x+4y=13

The next step is to eliminate a variable or do substitution. I personally find elimination easier. To eliminate the y, multiply the top equation by -2.

-10x-4y=-40
x+4y=13

The y's will cancel and you are left with:

-9x=-27
Divide by -9 on  both sides and you get x=3. Now you want to take 3 and substitute it back into one of the original equations. 

3+4y=13
Solve for y

4y=10
y=2.5

Plug both values into the top equation to check the values.

5(3)+2(2.5)=20
15+5=20
20=20

The answers are correct. Dog food is 3 dollars or euros and cat food is 2.50 euros. 

Please mark brainiest and good luck :D

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3 years ago
A bag contains 4 yellow balls, 5 red balls, and 6 blue balls.
I am Lyosha [343]

Answer:

A) The probability of picking a yellow ball from the bag is 26.66%.  

B) The probability of picking a blue ball from the bag is 40%.  

C) The probability of picking a yellow ball and then a blue ball is 11.42%.

Step-by-step explanation:

Since a bag contains 4 yellow balls, 5 red balls, and 6 blue balls, to determine what is the probability of picking a yellow ball from the bag, what is the probability of picking a blue ball from the bag and what is the probability of picking a yellow ball and then a blue ball after replacement, the following calculations must be performed:

A)

4 + 5 + 6 = 100

4 = X

15 = 100

4 = X

4 x 100/15 = X

400/15 = X

26.66 = X

Therefore, the probability of picking a yellow ball from the bag is 26.66%.

B)

15 = 100

6 = X

6 x 100/15 = X

600/15 = X

40 = X

Therefore, the probability of picking a blue ball from the bag is 40%.

C)

14 = 100

6 = X

6 x 100/14 = X

600/14 = X

42.85 = X

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0.1142 = X

Therefore, the probability of picking a yellow ball and then a blue ball is 11.42%.

4 0
3 years ago
Suppose A, R, and B are collinear on AB, and AR:AB= 1/5. What are the coordinates of R?
AfilCa [17]

Answer:

R(1.6, 0)

Step-by-step explanation:

Use the formula, (x, y) = (x_1 + k(x_2 - x_1), y_1 + k(y_2 - y_1)) to find the coordinates of point R, that partition the lie segment AB into the ratio 1/5.

Let,

A(1, -1) = (x_1, y_1)

B(4, 4) = (x_2, y_2)

Thus, plug in the values as follows:

R(x, y) = (1 + \frac{1}{5}(4 - 1), -1 + \frac{1}{5}(4 -(-1))

R(x, y) = (1 + \frac{1}{5}(3), -1 + \frac{1}{5}(4 + 1)

R(x, y) = (1 + \frac{1}{5}(3), -1 + \frac{1}{5}(5)

R(x, y) = (1 + \frac{3}{5}, -1 + \frac{5}{5})

R(x, y) = (\frac{5 + 3}{5}, -1 + 1)

R(x, y) = (\frac{8}{5}, 0)

R(x, y) = (1.6, 0)

The coordinates of point R, are (1.6, 0)

7 0
4 years ago
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