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3 years ago

7

The area of a rectangle is length × width. What is the length of a rectangular pool table that has a width of 5and 1 third feet

and an area of 50and 2 thirdssquare feet? Express your answer in simplest form.

1 answer:

Drupady [299]3 years ago

5 0

5 1/3 x 50 2/3=270.2

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Estimate the value 9.03 + 19.87 x 3.11 - 4.97

dybincka [34]

Answer:

82

Step-by-step explanation:

For this problem you would first round everything. 9.03 becomes 9, 19.87 becomes 20, 3.11 becomes 3 and 4.97 becomes 5. You then just do the problem. 9 + 20 = 29, multiplied by 3 makes 87, 87 - 5 = 82.

8 0

3 years ago

Which of the lines is perpendicular to the line shown in the graph

Nitella [24]

Answer:

The line passing through (-8, 10) and (-1, 4).

Step-by-step explanation:

Two lines are perpendicular if the product of their slopes is -1. The slope of the line in the picture is $7\over 6$ , so we should find a line with slope of $-6\over 7$ .

Note that the slope of the line in the last option is $-7\over 6$ .

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3 years ago

Divide 54 into two parts so that four times the greater equals five time the less

LUCKY_DIMON [66]

Let the both the parts be 'x' and 'y'
x>y
We know that 4x = 5y
so x = 5y/4
x + y = 54
Replacing x we get
(5y/4) + y = 54
(5y +4y)/4 = 54
9y = 216
y = 24
Replacing y in ' x+y = 54'
we get x = 30

Hence the larger part is 30 whereas the smaller part is 24

5 0

2 years ago

Look at the image for the question

saw5 [17]

It’s 16
You would multiply height (4) by the base (length(2) x width(2)=4) which is 16

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3 years ago

Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.

galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

$ut = \sqrt{ {6}^{2} + {5}^{2} } \\ \sqrt{36 + 25} \\ \sqrt{61 } \\ using \: cosine \: rule \\ cos \: u = \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times \sqrt{61} } \\ \\ = \frac{25 + 61 - 36}{78} \\ \\ = \frac{50}{78 } \\ \cos \: u = 0.64 \\ m \:u = 50.2$

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2 years ago