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Anna11 [10]
3 years ago
7

The area of a rectangle is length × width. What is the length of a rectangular pool table that has a width of 5and 1 third feet

and an area of 50and 2 thirdssquare feet? Express your answer in simplest form.
Mathematics
1 answer:
Drupady [299]3 years ago
5 0
5 1/3 x 50 2/3=270.2
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...........................
cupoosta [38]

Answer:

3/5 or 0.6

Step-by-step explanation:

Here, given the value of tan theta , we want to find the value of sine theta

Mathematically;

tan theta = 0pposite/adjacent

Sine theta = opposite/hypotenuse

Firstly we need the length of the hypotenuse

This can be obtained using the Pythagoras’ theorem which states that the square of the hypotenuse equals sum of the squares of the two other sides.

Let’s call the hypotenuse h

h^2 = 3^2 + 4^2

h^2 = 9 + 16

h^2 = 25

h = √(25)

h = 5

Now from the tan theta, we know that the opposite is 3

Thus, the value of the sine theta = 3/5 or simply 0.6

5 0
3 years ago
A boat sails 50 km on the bearing of 054º. How far is the ship north of its starting point
Otrada [13]

Answer:

12 A boat sails 50 km on the bearing 054º. How far is the ship north of its starting point? 13. 

Step-by-step explanation:

hope this helped!

3 0
3 years ago
Read 2 more answers
Find the x and y intercepts. Write your answer as x =<br> y =<br> 2x + 5y = 10
Ann [662]
The x-intercept is present where y = 0

2x + 5y - 10 = 0
2x - 10 = -5y
2x - 10 = -5(0)
2x = 10
x = 5

The y-intercept is present where x = 0

2x + 5y = 10
2x + 5y - 10 = 0
5y - 10 = -2(0)
5y = 10
y = 2
6 0
3 years ago
A bucket that weighs 6 lb and a rope of negligible weight are used to draw water from a well that is 80 ft deep. The bucket is f
zaharov [31]

Answer:

3200 ft-lb

Step-by-step explanation:

To answer this question, we need to find the force applied by the rope on the bucket at time t

At t=0, the weight of the bucket is 6+36=42 \mathrm{lb}

After t seconds, the weight of the bucket is 42-0.15 t \mathrm{lb}

Since the acceleration of the bucket is the force on the bucket by the rope is equal to the weight of the bucket.

If the upward direction is positive, the displacement after t seconds is x=1.5 t

Since the well is 80 ft deep, the time to pull out the bucket is \frac{80}{2}=40 \mathrm{~s}

We are now ready to calculate the work done by the rope on the bucket.

Since the displacement and the force are in the same direction, we can write

W=\int_{t=0}^{t=36} F d x

Use x=1.5 t and F=42-0.15 t

W=\int_{0}^{36}(42-0.15 t)(1.5 d t)

=\int_{0}^{36} 63-0.225 t d t

=63 \cdot 36-0.2 \cdot 36^{2}-0=3200 \mathrm{ft} \cdot \mathrm{lb}

=\left[63 t-0.2 t^{2}\right]_{0}^{36}

W=3200 \mathrm{ft} \cdot \mathrm{lb}

4 0
3 years ago
The perimeter of a square is four times the length of one side?
Aleksandr [31]

Answer:

yes

Step-by-step explanation:

6 0
3 years ago
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