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Anna11 [10]
2 years ago
7

The area of a rectangle is length × width. What is the length of a rectangular pool table that has a width of 5and 1 third feet

and an area of 50and 2 thirdssquare feet? Express your answer in simplest form.
Mathematics
1 answer:
Drupady [299]2 years ago
5 0
5 1/3 x 50 2/3=270.2
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Estimate the value 9.03 + 19.87 x 3.11 - 4.97
dybincka [34]

Answer:

82

Step-by-step explanation:

For this problem you would first round everything. 9.03 becomes 9, 19.87 becomes 20, 3.11 becomes 3 and 4.97 becomes 5. You then just do the problem. 9 + 20 = 29, multiplied by 3 makes 87, 87 - 5 = 82.

8 0
2 years ago
Which of the lines is perpendicular to the line shown in the graph
Nitella [24]

Answer:

The line passing through (-8, 10) and (-1, 4).

Step-by-step explanation:

Two lines are perpendicular if the product of their slopes is -1. The slope of the line in the picture is 7\over 6, so we should find a line with slope of -6\over 7.

Note that the slope of the line in the last option is -7\over 6.

4 0
3 years ago
Divide 54 into two parts so that four times the greater equals five time the less​
LUCKY_DIMON [66]
Let the both the parts be 'x' and 'y'
x>y
We know that 4x = 5y
so x = 5y/4
x + y = 54
Replacing x we get
(5y/4) + y = 54
(5y +4y)/4 = 54
9y = 216
y = 24
Replacing y in ' x+y = 54'
we get x = 30

Hence the larger part is 30 whereas the smaller part is 24
5 0
2 years ago
Look at the image for the question
saw5 [17]
It’s 16
You would multiply height (4) by the base (length(2) x width(2)=4) which is 16
5 0
3 years ago
Find m∠U.<br> Write your answer as an integer or as a decimal rounded to the nearest tenth.
galina1969 [7]

Answer:

Answer:

50.2

Step-by-step explanation:

ut =  \sqrt{ {6}^{2}  +  {5}^{2} }   \\  \sqrt{36 + 25}  \\  \sqrt{61 }  \\ using \: cosine \: rule \\ cos \: u =  \frac{ {5}^{2} + 61 - 36 }{2 \times 5 \times  \sqrt{61} }  \\  \\  =  \frac{25 + 61 - 36}{78}  \\  \\  = \frac{50}{78 }  \\  \cos \: u = 0.64 \\ m \:u = 50.2

6 0
2 years ago
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