Answer:
he has 26 1/6 square meters left.
Step-by-step explanation:
first, i divided 78 1/2 by 3, because he got 2 3rds done with only 1/3 left.
when i did that i got 26 1/6.
i highly recommend photmath app. it makes equations like that easy to put together and explain easily.
I think that the answer is 8
Answer:
Step-by-step explanation:
1) the triangle is a right angle triangle.
From the given right angle triangle,
With 67° as the reference angle,
x represents the adjacent side of the right angle triangle.
17 represents the opposite side of the right angle triangle.
To determine x, we would apply
the Tangent trigonometric ratio.
Tan θ = opposite side/adjacent side.
Therefore,
Tan 67 = 17/x
xTan 67 = 17
x = 17/Tan 67
x = 17/2.3559
x = 7.22
2) From the given right angle triangle, with 24° as the reference angle,
x represents the opposite side of the right angle triangle.
12 represents the adjacent side of the right angle triangle.
To determine x, we would apply
the Tangent trigonometric ratio.
Tan θ = opposite side/adjacent side.
Therefore,
Tan 24 = x/12
x = 12Tan 24
x = 12 × 0.4452
x = 5.34
Answer:

Step-by-step explanation:
we are given
the sum,common difference and nth term of a geometric sequence
we want to figure out the first term
recall geometric sequence

we are given that
thus substitute:

to figure out
we need to figure out the equation
simplify denominator:

simplify square:

simplify substraction:

simplify complex fraction:

calculate reciprocal:

reduce fraction:

multiply both sides by 4/7:

reduce fraction:

simplify multiplication:

hence,

Answer:
A, C, D and K
Step-by-step explanation:
Inequalities:
y ≤ −2x + 10 and y >1/2x-2
<u>Finding zeros for the first inequality:</u>
- x=0 ⇒ y= 10, point (0, 10)
- y=0 ⇒ x= 5, point (5, 0)
- Locating these 2 points and connecting to get the first line.
Space to the left of this line (as y≤ ) is the solution for this inequality, any points on this line are inclusive.
<u>Finding zeros for the second inequality:</u>
- x=0 ⇒ y= -2, point (0, -2)
- y= 0 ⇒ x= 4, point (4, 0)
- Locating these points and connecting to get the second line.
Space above this line (as y > sign) is the solution for this inequality, any points on this line are not inclusive.
Now we have the space of intersection of the above inequalities.
So the points in same section are the solution.
They are:
See attached for explanation