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goblinko [34]
4 years ago
10

A mason needs 22 bricks to make a stoop. So far he carried 15 into the site. How many more bricks must he carry

Mathematics
2 answers:
Bond [772]4 years ago
8 0
22-15=7. Is that right?
pav-90 [236]4 years ago
8 0
22-15=7................................................................
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Which is larger 34.653 or 3.4653
mash [69]
34.653 is the largest
6 0
3 years ago
This was given to me during a summative test and the teacher didn't bother giving me the correction. I just cannot figure it out
Dmitry [639]
  • Base be y

ATQ

\\ \sf\longmapsto xy=6050\dots 1

\\ \sf\longmapsto 2(x+y)=220\implies x+y=110\dots 2

Now

\\ \sf\longmapsto (x+y)^2=x^2+y^2+2xy

\\ \sf\longmapsto 110^2-2(6050)=x^2+y^2

\\ \sf\longmapsto 12100-12100=x^2+y^2

\\ \sf\longmapsto x^2+y^2=0\dots(3)

From all equations

\\ \sf\longmapsto (x-y)^2=x^2+y^2-2xy

\\ \sf\longmapsto (x-y)^2=0-2(6050)

\\ \sf\longmapsto (x-y)^2=-12100

\\ \sf\longmapsto (x-y)=110\dots(4)

Now

Adding 3 and 4

\\ \sf\longmapsto 2x=220

\\ \sf\longmapsto x=110m

One side won't be covered hence

  • y=2(110)=220m
7 0
3 years ago
Read 2 more answers
Mr. Blue drove from Allston to Brockton, a distance of 105 miles. On his way back, he increased his speed by 10 mph. If the jour
andrew-mc [135]

Answer:

His original speed was 60 mph.

Step-by-step explanation:

The average speed formula is shown below:

speed = distance / time

For the first leg of the trip Mr. Blue drove at a speed of "x" mph, for a distance of 105 miles, therefore the time that took to complete the trip is:

time 1 = distance / speed

time 1 = 105 / x h

On the second leg of the trip Mr. Blue drove faster at a speed of "x + 10" mph, so the time it took him to complete the trip was 15 minutes less, therfore:

time 2 = time1 - (15/60) = (105/x) - 0.25 = (105 - 0.25*x)/x h

Applyint the time and speed from the second leg to the average speed formula we have:

x + 10 = {105/[(105 - 0.25*x)/x]}

x + 10 = 105*x/(105 - 0.25*x)

(x + 10)*(105 - 0.25*x) = 105*x

105*x + 1050 -0.25*x² - 2.5*x = 105*x

-0.25*x² -2.5*x + 1050 = 0 /(-0.25)

x² + 10*x - 4200 = 0

x1 = [-(10) + sqrt((10)² - 4*(1)*(-4200))]/2 = 60

x2 = [-(10) - sqrt((10)² - 4*(1)*(-4200))]/2 = -70

Since his speed couldn't be negative the only possible value was 60 mph.

5 0
3 years ago
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Two sections took the same vocabulary qui. Use the 5-number summary 20,30 35 45 80) to construct a boxplot for Section and use t
gulaghasi [49]

Answer:

C. There are the same number of scores in Section and Section

Step-by-step explanation:

The median of section I is greater than the median of section L. Median is the middle value or midpoint in the data set. In the given quiz the data set has different numbers for every section and therefore the values are not same. The data set has 75% of scores in section il which is higher than the section L.

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It takes 124 minutes to lift 4 tires on to a lorry how long would it take him to fit 6 tires in a lorry
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Answer:186

Step-by-step explanation:

you divide 124 by 2 and you just add the half to 124.

6 0
3 years ago
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