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Over [174]
3 years ago
15

1. which of the following is the equation of a line that is parallel to the line y=4x+5?

Mathematics
1 answer:
Mashutka [201]3 years ago
5 0
1. C: y=4x+3
2. A: <span>-5x-2y=1
</span>3. B: <span>y=1/3x
</span>4. D: <span>y=1/2x+4</span>
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BRAINLIEST!!! Can someone tell me how to graph inequalities?
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Answer:

whichever way the opening of the sign points go the opposite. if it is less than or equal to, closed circle

Step-by-step explanation:

>

the line would point this way -->

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Why do equivalent ratios form a straight line when<br> graphed? Explain.
irina1246 [14]

Answer:

The y-values of equivalent ratios increase at the same rate as their x-values. The vertical distance between points is constant, and the horizontal distance between points is constant. This forms a straight line.

Step-by-step explanation:

Equivalent proportions (which are, as a result, equal parts) are two proportions that express a similar connection between numbers. We can make comparable proportions by duplicating or separating both the numerator and denominator of a given proportion by a similar number.

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8 0
2 years ago
Find the equation of the line that passes through (-1,2) and is perpendicular to y=1 – 2x.
nika2105 [10]

Answer:

is the line are perpendicular then the product of there slope is -1

the slope of the first equation is 2

Step-by-step explanation:

m1+m2=-1

2+m2=-1

m2=-1-2

m2=-3

so the second equation became y=-3x+C

then insert the point (-1,2)

2=-3*-1+C

2=3+C

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2 years ago
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Find values of  that satisfy the equation for 0º    360º and 0  θ  2 . Give answers in degrees and radians.
suter [353]

Answer:

\theta = 30^\circ, 330^\circ

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

Step-by-step explanation:

Given [Missing from the question]

Equation:

cos\theta = \frac{\sqrt 3}{2}

Interval:

0 \le \theta \le 360

0 \le \theta \le 2\pi

Required

Determine the values of \theta

The given expression:

cos\theta = \frac{\sqrt 3}{2}

... shows that the value of \theta is positive

The cosine of an angle has positive values in the first and the fourth quadrants.

So, we have:

cos\theta = \frac{\sqrt 3}{2}

Take arccos of both sides

\theta = cos^{-1}(\frac{\sqrt 3}{2})

\theta = 30 --- In the first quadrant

In the fourth quadrant, the value is:

\theta = 360 -30

\theta = 330

So, the values of \theta in degrees are:

\theta = 30^\circ, 330^\circ

Convert to radians (Multiply both angles by \pi/180)

So, we have:

\theta = \frac{30 * \pi}{180}, \frac{330 * \pi}{180}

\theta = \frac{\pi}{6}, \frac{33 * \pi}{18}

\theta = \frac{\pi}{6}, \frac{11 * \pi}{6}

\theta = \frac{\pi}{6}, \frac{11\pi}{6}

8 0
2 years ago
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