(stupid answers will get reported)(alots of points)

A toy company intends to ship out its entire stock of 10,254 toy trucks, and three times as many toy cars. If each box holds 35

svetoff [14.1K]

There are 10,254 toy trucks

and 10,254 * 3 = 30,762 toy cars.

In total, there are 10,254+30,762= 41,016 toys

when we divide 41,016 by 35, the quotient is the number of the full boxes, and the remainder is the number of toys left.

41,016=35*1171+31

Answer: 1171 full boxes, 31 toys left for the last box

6 0

3 years ago

HELP ME WITH THIS QUESTION ASAP

Stels [109]

Factor out 12x^3y^2

12x^3y^2(3y^2+5x^ 2 y z^2 -1)

8 0

3 years ago

SAVE ME. Please Answer my Questions Clevers.

Vladimir [108]

Answer:

See below

Step-by-step explanation:

Q1. if a counting number is selected at random from a set of whole number less than or equal to 20 find the probability of getting:

Counting numbers are Natural numbers: $\mathbb{N}$

Also, we have Whole numbers. Despite not having an official symbol, I usually denote the set as $\mathbb{Z}_{\ge 0}$

Whole numbers less than or equal to 20: $A\leq 20, A \subset \mathbb{Z}_{\ge 0} \\\implies A=\{0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20\}$

A. Prime numbers

From the set A, the prime numbers are 2, 3, 5, 7, 11, 13, 17, 19.

Once we have 21 numbers in total and 8 prime numbers, the probability is:

$P=\frac{8}{21} \approx 40\%$

B. Composite numbers

From the set A, the composite numbers are 4, 6, 8, 9, 10, 12, 14, 15, 16, 18, 20.

Once we have 21 numbers in total and 11 composite numbers, the probability is:

$P=\frac{11}{21} \approx 52\%$

C. Divisible by three

From the set A, the numbers divisible by three are 3, 6, 9, 12, 15, 18.

Once we have 21 numbers in total and 6 numbers divisible by three, the probability is:

$P=\frac{6}{21} \approx 30\%$

D. Square of 2

From the set A, the numbers square of 2 are 0, 1, 4, 9, 16.

$\sqrt{0} =0$

$\sqrt{1} =1$

$\sqrt{4} =2$

$\sqrt{9} =3$

$\sqrt{16} =4$

Once we have 21 numbers in total and 5 numbers square of 2 , the probability is:

$P=\frac{5}{21} \approx 24\%$

Q2. The opposite angle of acyclic quadrilaterals is in the ratio of 2:3. Find the degree measure of each opposite angle?

Once they're opposite, they add up to 180º

$2x+3x=180 \implies 5x=180 \implies x=36$

The first angle is 72º

The second angle is 108º

Q3. what is the solution set of 9x-4<13x-7 (domain, x e z) ?

$x \in \mathbb{Z}\\$

$x>\frac{3}{4}$

$x\in \left(\frac{3}{4},\infty \right)$

Q4. if three fourth of a number is one tenths, what is the number?

$\frac{3}{4} x =\frac{1}{10} \implies 3x=\frac{4}{10} \implies \boxed{x = \frac{2}{15}}$

Q5. which one is the equation of the line passing through the origin and having a slope 4?

$y=mx+b$

$m: \text{slope}$

$b: \text{y-intercept}$

B. Y= 4x

7 0

3 years ago

What is the total amount in an investment of $3500 that was compounded quarterly for 8 years at a rate of 5%?

erica [24]

Answer:

Principal = 3500

Time = 8 years

We are given that compound quarterly

So, No. of compounds per year = 2

Rate of interest = 5%

Formula : $A=P(1+\frac{r}{n})^{nt}$

Substitute the values :

$A=3500(1+\frac{0.05}{2})^{2 \times 2}$

$A=3863.345$

Interest = 3863.345 - 3500 = 363.345

Hence the total amount in an investment of $3500 that was compounded quarterly for 8 years at a rate of 5% is $3863.345 and the interest that was made on that account mentioned is $363.345

8 0

4 years ago

(2.03)

ExtremeBDS [4]

Step 3 is the frist incorrect step it should be: 2x-3=3 or 2x-3=-3

3 0

3 years ago

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