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I am Lyosha [343]
3 years ago
6

What is the quotient of 8/9 and 1 1/3

Mathematics
1 answer:
Dovator [93]3 years ago
5 0
8/9 divided by 1 1/3 is 2/3
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Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used. Match each verbal description of a sequen
galben [10]

Answer:

I think the question is wrong so, I will try and explain with some right questions

Step-by-step explanation:

We are give 6 sequences to analyse

1. an = 3 · (4)n - 1

2. an = 4 · (2)n - 1

3. an = 2 · (3)n - 1

4. an = 4 + 2(n - 1)

5. an = 2 + 3(n - 1)

6. an = 3 + 4(n - 1)

1. This is the correct sequence

an=3•(4)^(n-1)

If this is an

Let know an+1, the next term

an+1=3•(4)^(n+1-1)

an+1=3•(4)^n

There fore

Common ratio an+1/an

r= 3•(4)^n/3•(4)^n-1

r= (4)^(n-n+1)

r=4^1

r= 4, then the common ratio is 4

Then

First term is when n=1

an=3•(4)^(n-1)

a1=3•(4)^(1-1)

a1=3•(4)^0=3.4^0

a1=3

The first term is 3 and the common ratio is 4, it is a G.P

2. This is the correct sequence

an=4•(2)^(n-1)

Therefore, let find an+1

an+1=4•(2)^(n+1-1)

an+1= 4•2ⁿ

Common ratio=an+1/an

r=4•2ⁿ/4•(2)^(n-1)

r=2^(n-n+1)

r=2¹=2

Then the common ratio is 2,

The first term is when n =1

an=4•(2)^(n-1)

a1=4•(2)^(1-1)

a1=4•(2)^0

a1=4

It is geometric progression with first term 4 and common ratio 2.

3. This is the correct sequence

an=2•(3)^(n-1)

Therefore, let find an+1

an+1=2•(3)^(n+1-1)

an+1= 2•3ⁿ

Common ratio=an+1/an

r=2•3ⁿ/2•(3)^(n-1)

r=3^(n-n+1)

r=3¹=3

Then the common ratio is 3,

The first term is when n =1

an=2•(3)^(n-1)

a1=2•(3)^(1-1)

a1=2•(3)^0

a1=2

It is geometric progression with first term 2 and common ratio 3.

4. I think this correct sequence so we will use it.

an = 4 + 2(n - 1)

Let find an+1

an+1= 4+2(n+1-1)

an+1= 4+2n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=4+2n-(4+2(n-1))

d=4+2n-4-2(n-1)

d=4+2n-4-2n+2

d=2.

The common difference is 2

Now, the first term is when n=1

an=4+2(n-1)

a1=4+2(1-1)

a1=4+2(0)

a1=4

This is an arithmetic progression of common difference 2 and first term 4.

5. I think this correct sequence so we will use it.

an = 2 + 3(n - 1)

Let find an+1

an+1= 2+3(n+1-1)

an+1= 2+3n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=2+3n-(2+3(n-1))

d=2+3n-2-3(n-1)

d=2+3n-2-3n+3

d=3.

The common difference is 3

Now, the first term is when n=1

an=2+3(n-1)

a1=2+3(1-1)

a1=2+3(0)

a1=2

This is an arithmetic progression of common difference 3 and first term 2.

6. I think this correct sequence so we will use it.

an = 3 + 4(n - 1)

Let find an+1

an+1= 3+4(n+1-1)

an+1= 3+4n

This is not GP

Let find common difference(d) which is an+1 - an

d=an+1-an

d=3+4n-(3+4(n-1))

d=3+4n-3-4(n-1)

d=3+4n-3-4n+4

d=4.

The common difference is 4

Now, the first term is when n=1

an=3+4(n-1)

a1=3+4(1-1)

a1=3+4(0)

a1=3

This is an arithmetic progression of common difference 4 and first term 3.

5 0
3 years ago
Which relation does not represent a function​
Nastasia [14]

Answer:

For example, if given a graph, you could use the vertical line test; if a vertical line intersects the graph more than once, then the relation that the graph represents is not a function.

Hope this helped

3 0
3 years ago
A game increased in price by 1/2 . After the increase it was priced at £27. What was the original price of the game? (Hegarty Ma
lukranit [14]

Answer:

£18

Step-by-step explanation:

Let

x = original price of the game

Increase in price = 1/2

New price = £27

x + 1/2x = £27

2x+x/2 = 27

3/2x = 27

x = 27 ÷ 3/2

= 27 × 2/3

= 54 / 3

x = £18

Therefore, the original price of the game is £18

4 0
3 years ago
Read 2 more answers
Brainliest to first answer correct.
suter [353]

Answer:

Option A is correct.

Step-by-step explanation:

The height of the rectangular pack is h1 = 4r

The height of the parallelogram = 2r + the height of equilateral triangles with a side of 2r

The height of equilateral triangle with a side of 2r = (side)/2*√3

=(2r)/2 *√3 = r√3

The height of the parallelogram h2 = 2r+r√3 = r(2+√3)

So,the ratio of h1 to h2 is :

4r : r(2 +√3)

Cancelling r we get

Hence, the ratio is  4 : 2 +√3

5 0
3 years ago
Solve for n<br> -18 = 6<br> 3
mihalych1998 [28]

Answer:

−

6

=

3

7

n

Step-by-step explanation:

Rewrite the equation as  

3

7

n

=

−

6

.

3

7

n

=

−

6

Multiply both sides of the equation by  

7

3

.

7

3

⋅

3

7

⋅

n

=

7

3

⋅

−

6

Simplify both sides of the equation.

Tap for more steps...

n

=

−

14

6 0
3 years ago
Read 2 more answers
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