X у 5 -2 7. 4 9 10 11 16

A random sample of 64 bags of white cheddar popcorn weighed, on average, 5.23 ounces with a standard deviation of 0.24 ounce.

emmasim [6.3K]

Answer:

We conclude that cheddar popcorn weighed less than 5.5 ounces.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ =5.5 ounces

Sample mean, $\bar{x}$ = 5.23 ounces

Sample size, n = 64

Alpha, α = 0.05

Sample standard deviation, σ = 0.24 ounce.

First, we design the null and the alternate hypothesis

$H_{0}: \mu = 5.5\text{ ounces}\\H_A: \mu < 5.5\text{ ounces}$

We use One-tailed z test to perform this hypothesis.

Formula:

$z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{s}{\sqrt{n}} }$

Putting all the values, we have

$z_{stat} = \displaystyle\frac{5.23 - 5.5}{\frac{0.24}{\sqrt{64}} } = -9$

Now, $z_{critical} \text{ at 0.05 level of significance } =-1.645$

Since,

$z_{stat} < z_{critical}$

We reject the null hypothesis and accept the alternate hypothesis. Thus, we conclude that cheddar popcorn weighed less than 5.5 ounces.

3 0

3 years ago

I need help!! On this question please hurry

hichkok12 [17]

Step-by-step explanation:

Given:

Central Enlargement.

AC=4

AB=5

BC=3

Opp=3

Hyp=5

Required:

Sin<A

Formula:

Sin<A=Opp/hyp

Solution:

Sin<A=Opp/Hyp

Sin<A=3/5 or 0.6

5 0

3 years ago

Round the following numbers to the nearest 10. The numbers they have is 13,21,29

earnstyle [38]

Answer:

13: 10

21: 20

29: 30

Step-by-step explanation:

5 0

3 years ago

The cosine of 23° is equivalent to the sine of what angle

Archy [21]

Answer:

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

(There are more values since we can go around the circle from 67 degrees numerous times.)

Step-by-step explanation:

You can use a co-function identity.

The co-function of sine is cosine just like the co-function of cosine is sine.

Notice that cosine is co-(sine).

Anyways co-functions have this identity:

$\cos(90^\circ-x)=\sin(x)$

or

$\sin(90^\circ-x)=\cos(x)$

You can prove those drawing a right triangle.

I drew a triangle in my picture just so I can have something to reference proving both of the identities I just wrote:

The sum of the angles is 180.

So 90+x+(missing angle)=180.

Let's solve for the missing angle.

Subtract 90 on both sides:

x+(missing angle)=90

Subtract x on both sides:

(missing angle)=90-x.

So the missing angle has measurement (90-x).

So cos(90-x)=a/c

and sin(x)=a/c.

Since cos(90-x) and sin(x) have the same value of a/c, then one can conclude that cos(90-x)=sin(x).

We can do this also for cos(x) and sin(90-x).

cos(x)=b/c

sin(90-x)=b/c

This means sin(90-x)=cos(x).

So back to the problem:

cos(23)=sin(90-23)

cos(23)=sin(67)

So 67 degrees is one value that we can take the sine of such that is equal to cos(23 degrees).

6 0

2 years ago

If point Q does not lie on the x-axis or the y-

Harman [31]

E. II or IV only because it will have different signs if point Q was in either of those quadrants

4 0

2 years ago