I think it is 3 A but it is hard to know what the question is asking... but my logic is that 3 A is right because A = 1+2 = 3
Let r(cos O + i sin O) be a cube root of 125(cos 288 + i sin 288)
then
r^3(cos O + i sin O)^3 = 125(cos 288 + i sin 28)
so r^3 = 125 and cos 3O + i sin 3O = cos 288 + i sin 288
so r = 5 and 3O = 288 + 360p and O = 96 + 120p
so one cube root is 5 (cos 96 + i sin 96)
Im a little rusty at this stuff Its been a long time.
Im not sure of the other 2 roots
sorry cant help you any more
Three hundred thousand four thousand one
300000 +4000+1
We are asked to sum the two trinomials
. We can start by using the distributive property to remove the parenthesis, giving us
. Next, when we combine like terms, we get
. Hope this helped!
