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2 years ago

The code for puzzle one escape the rooms

Mathematics

1 answer:

Anna35 [415]2 years ago

4 0

Answer:

there Is no question to that cluld you explain. sorry I don't know how to comment.

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Complete the equation: 4 1/2 c = ? oz

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3 years ago

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7(-3 + 2u) simplified

Allushta [10]

<span>7(-3 + 2u) simplified is </span> $-21+14u$

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3 years ago

I need help with this

noname [10]

Answer:

the second one

Step-by-step explanation:

When subtracting a negative, the negative turns to a positive, so in this case, -14- -8 would be the same as -14 + 8

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3 years ago

Select all choices which could lead to a biased result. randomly calling telephone numbers to ask if people are satisfied with t

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3 years ago

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The length and width of a rectangle are measured as 55 cm and 49 cm, respectively, with an error in measurement of at most 0.1 c

valentina_108 [34]

Answer:

The maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

Step-by-step explanation:

The area of a rectangle with length $L$ and width $W$ is $A= L\cdot W$ so the differential of <em>A</em> is

$dA=\frac{\partial A}{\partial L} \Delta L+\frac{\partial A}{\partial W} \Delta W$

$\frac{\partial A}{\partial L} = W\\\frac{\partial A}{\partial W}=L$ so

$dA=W\Delta L+L \Delta W$

We know that each error is at most 0.1 cm, we have $|\Delta L|\leq 0.1$ , $|\Delta W|\leq 0.1$ . To find the maximum error in the calculated area of the rectangle we take $\Delta L = 0.1$ , $\Delta W = 0.1$ and $L=55$ , $W=49$ . This gives

$dA=49\cdot 0.1+55 \cdot 0.1$

$dA=10.4$

Thus the maximum error in the calculated area of the rectangle is $10.4 \:cm^2$

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3 years ago