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den301095 [7]
3 years ago
14

Which equation has a k-value of -12A. y=-12xB. y=12+12xC. y=x-12D. y=12x+1

Mathematics
1 answer:
CaHeK987 [17]3 years ago
3 0
I would say A. I'm assuming this is to do with the equation y=kx, therefore A has the k value of -12
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2x + y = 3<br> x = 2y - 1
Ad libitum [116K]
<span>2x+ y = 3
x = 2y - 1 
Make sure there are NO SPACES in your answer. Include a comma in your answer.
It looks like I could substitute the x=2y-1. Into 2x+y=3
2(2y-1)+y=3
4y-2+y=3
5y=5
y=1
x=2(1)-1
x=1

(1,1)
CHECK
2x+y=3
2(1)+(1)=3
2+1=3
3=3
Left hand side=Right hand side 
Check other equation 
x=2y-1
1=2(1)-1
1=1
Therefore the solution is (1,1). Since the left hand side= right hand side in each equation</span>
8 0
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