Question

If f(x) = 1/9 x-2 , what is f–1(x)?

Answer 1

Answer:

$f^{-1}(x)=9x+2$

Step-by-step explanation:

Given: $f(x)=\dfrac{1}{9}(x-2)$

We need to find the inverse of f(x).

Step 1: Set f(x) = y

$y=\dfrac{1}{9}(x-2)$

Step 2: Switch x and y

$x=\dfrac{1}{9}(y-2)$

Step 3: Solve for y, Isolate y

$x=\dfrac{1}{9}(y-2)$

Multiply by 9 both sides

$9x=y-2$

Add 2 both sides

$9x+2=y$

$y=f^{-1}(x)$

Hence, $f^{-1}(x)=9x+2$

Answer 2

Hello,

y=1/9 x-2
==>x=1/9 y -2
==>9x=y-18
==>y=9x+18

f^(-1)(x)=9x+18