I don't know the answer because i'm awful at math, but we're both in CMASAS! lol
Answer:
just use a calculator
Step-by-step explanation:
or use photo shop to get ez answers
Answer:
A must be true
Step-by-step explanation:
Since ABE and angle ACE are right angles the rest of the 2 angles are right angles either therefore EC = AB
The slope of the given line is found from the coefficient of x after dividing the equation by 2.
.. y = -3x +4
The given line has slope -3.
A perpendicular line will have a slope that is the negative reciprocal of this:
.. -1/(-3) = 1/3
This corresponds to your 3rd choice.
<h3>
Answer: 40</h3>
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Explanation:
JQ is longer than QN. We can see this visually, but the rule for something like this is the segment from the vertex to the centroid is longer compared to the segment that spans from the centroid to the midpoint.
See the diagram below.
The ratio of these two lengths is 2:1, meaning that JQ is twice as long compared to QN. This is one property of the segments that form when we construct the centroid (recall that the centroid is the intersection of the medians)
We know that JN = 60
Let x = JQ and y = QN
The ratio of x to y is x/y and this is 2/1
x/y = 2/1
1*x = y*2
x = 2y
Now use the segment addition postulate
JQ + QN = JN
x + y = 60
2y + y = 60
3y = 60
y = 60/3
y = 20
QN = 20
JQ = 2*y = 2*QN = 2*20 = 40
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We have
JQ = 40 and QN = 20
We see that JQ is twice as larger as QN and that JQ + QN is equal to 60.