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Anon25 [30]
2 years ago
15

FIND THE SUM: (6x^2-2x-3)+(x^2-3x+1) 1.6x^2+6x+3 2.7x^2+5x+2 3.7x^2-5x-2

Mathematics
1 answer:
Butoxors [25]2 years ago
5 0

8x^2-5x-2

method

open bracket

6x^2-2x-3+x^2-3x+1

collect like terms

6x^2+2x^2-3-3x+1

8x^2-3-3x+1

again collect like terms

8x^2-2x-3x-3+1

8x^2-5x-3+1. (-×-=+ addition but keeping sign minus

8x-5x-2. (-×+=-)

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Help pls!!!!!!!!!!!!!!
Sholpan [36]

Answer:

46°

Step-by-step explanation:

tan Ф = 21/20

Ф = tan-1 (21/20)

= 46°

8 0
3 years ago
HELP BRAINLIEST! I think its none of the above
mamaluj [8]

Answer:

180 degrees

Explanation:

So if it was 90 degrees it would be the same thing just fliped. 180 means that it did a half a rotaion so it would be the mirrored of the original object. That is what we see the second figure is mirrored of the other. 90 degrees also would be different.

<h2><u>Answer: 180 degrees</u></h2>

7 0
2 years ago
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What is the center of the circle described by the equation (x - 2)^2 +(y + 7)^2 =169
Marizza181 [45]

Answer:

The center is (2, -7)

Step-by-step explanation:

A circle is given by

(x-h)^2 + (y-k)^2 = r^2

where(h,k) is the center and r is the radius

(x - 2)^2 +(y + 7)^2 =169

(x - 2)^2 +(y -  -7)^2 =13^2

The center is (2, -7) and the radius is 13

4 0
2 years ago
If for two non-zero vectors a,b : ∣a+b∣=∣a−b∣ then angle between them is:______a. 0b. 45c. 60d. 90
Eddi Din [679]

Answer:

90^\circ

Step-by-step explanation:

Given two non zero vectors, \vec a, \vec b.

Let the angle between the two vectors = \theta

Given that:

|\vec a+\vec b|=|\vec a-\vec b|

Let us have a look at the formula for magnitude of addition of two vectors:

|\vec x+\vec y|=\sqrt{x^2+y^2+2xycos\theta}

Where \theta is the angle between the two vectors.

formula for magnitude of subtraction of two vectors:

|\vec x-\vec y|=\sqrt{x^2+y^2-2xycos\theta}

As per the given condition:

\sqrt{a^2+b^2+2abcos\theta}=\sqrt{a^2+b^2-2abcos\theta}

Squaring both sides:

a^2+b^2+2abcos\theta=a^2+b^2-2abcos\theta\\\Rightarrow 2abcos\theta=-2abcos\theta\\\Rightarrow cos\theta = -cos\theta\\\Rightarrow 2cos\theta = 0\\\Rightarrow cos\theta = 0\\\Rightarrow \theta = 90^\circ

So, the angle between the two vectors is: 90^\circ

7 0
2 years ago
When fourfour basketball players are about to have a​ free-throw competition, they often draw names out of a hat to randomly sel
sesenic [268]

Answer:

fortty fou

Step-by-step explanation:

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