Answer:
I can't see the picture right, it's backward sorry
Step-by-step explanation:
edit the picture and take a better one
Answer:
Step-by-step explanation:
Given that a popcorn company builds a machine to fill 1 kg bags of popcorn. They test the first hundred bags filled and find that the bags have an average weight of 1,040 grams with a standard deviation of 25 grams.
i.e. Sample mean = 1040 and
Sample std dev s = 25 gm
Sample size n = 100
Hence by central limit theorem we have the sample mean follows a normal distribution with mean =1040 and std dev = s = 25 gm
![\bar X = N(1040,25)](https://tex.z-dn.net/?f=%5Cbar%20X%20%3D%20N%281040%2C25%29)
Normal curve would be with mean 1040 and std deviatin 25
b) P(X>1115)
= 1-0.9987
=0.0013
i.e. 0.13% would receive a bag that had a weight greater than 1115 grams
Answer:
42580 miles
Step-by-step explanation:
Mean = ![\mu = 47500](https://tex.z-dn.net/?f=%5Cmu%20%3D%2047500)
![\sigma = 3000](https://tex.z-dn.net/?f=%5Csigma%20%3D%203000)
The manufacturer does not want to replace more than 5% of the tires
![P(X\leq x)=5\%](https://tex.z-dn.net/?f=P%28X%5Cleq%20x%29%3D5%5C%25)
![P(\frac{x-\mu}{\sigma}\leq \frac{x-47500}{3000})=0.05](https://tex.z-dn.net/?f=P%28%5Cfrac%7Bx-%5Cmu%7D%7B%5Csigma%7D%5Cleq%20%5Cfrac%7Bx-47500%7D%7B3000%7D%29%3D0.05)
By using normal table values :
![\frac{x-47500}{3000}=-1.64](https://tex.z-dn.net/?f=%5Cfrac%7Bx-47500%7D%7B3000%7D%3D-1.64)
![x=(-1.64 \times 3000)+47500](https://tex.z-dn.net/?f=x%3D%28-1.64%20%5Ctimes%203000%29%2B47500)
![x=42580](https://tex.z-dn.net/?f=x%3D42580)
Hence the approximate number of miles for the warranty is 42580 miles
Answer:
22.75
Step-by-step explanation:
you substitute the 7 in for c and d. Following PEMDAS, you would then do (1/4) multiplied by 7 and 3 times 7. add those 2 together and you get 22.75 :)