5 floors because 16.25/3.25 equals 5
Step-by-step explanation:
find the best fitting common multiple between 12 and 8.
let's start with the basic
8×12 = 96
96 fits 3 times into 300 with a remainder of 12.
so, 96 × 3 = 288
that means 288/12 = 24 packages of hot dogs and 288/8 = 36 packages of buns to create exactly 288 hot dogs.
any packages more or less would make the number of available buns and hot dogs "uneven".
Answer:
option B) Bar 2
Step-by-step explanation:
The histogram represent the number of gallons of gasoline on x axis.
The number of drivers purchase weekly on y axis.
In this histogram 5 Bars are shown.
First bar represents = 5 drivers
Second bar represents = 6 drivers
Third bar represents = 1 driver
Fourth bar represents = 3 drivers
Fifth bar represents = = 4 drivers
So the second bar represents the the number of gallons most drivers purchased during the week.
Therefore, option B) Bar 2 is the correct answer.
Answer:
The sample size used to compute the 95% confidence interval is 1066.
Step-by-step explanation:
The (1 - <em>α</em>)% confidence interval for population proportion is:
![CI=\hat p\pm z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}](https://tex.z-dn.net/?f=CI%3D%5Chat%20p%5Cpm%20z_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D)
The 95% confidence interval for proportion of the bank's customers who also have accounts at one or more other banks is (0.45, 0.51).
To compute the sample size used we first need to compute the sample proportion value.
The value of sample proportion is:
![\hat p=\frac{Upper\ limit+Lower\ limit}{2}=\frac{0.45+0.51}{2}=0.48](https://tex.z-dn.net/?f=%5Chat%20p%3D%5Cfrac%7BUpper%5C%20limit%2BLower%5C%20limit%7D%7B2%7D%3D%5Cfrac%7B0.45%2B0.51%7D%7B2%7D%3D0.48)
Now compute the value of margin of error as follows:
![MOE=\frac{Upper\ limit-Lower\ limit}{2}=\frac{0.51-0.45}{2}=0.03](https://tex.z-dn.net/?f=MOE%3D%5Cfrac%7BUpper%5C%20limit-Lower%5C%20limit%7D%7B2%7D%3D%5Cfrac%7B0.51-0.45%7D%7B2%7D%3D0.03)
The critical value of <em>z</em> for 95% confidence level is:
![z_{\alpha/2}=z_{0.05/2}=z_{0.025}=1.96](https://tex.z-dn.net/?f=z_%7B%5Calpha%2F2%7D%3Dz_%7B0.05%2F2%7D%3Dz_%7B0.025%7D%3D1.96)
Compute the value of sample size as follows:
![MOE=z_{\alpha/2}\sqrt{\frac{\hat p(1-\hat p)}{n}}\\0.03=1.96\times \sqrt{\frac{0.48(1-0.48)}{n}}\\(\frac{0.03}{1.96})^{2}=\frac{0.48(1-0.48)}{n}\\n=1065.404\\n\approx1066](https://tex.z-dn.net/?f=MOE%3Dz_%7B%5Calpha%2F2%7D%5Csqrt%7B%5Cfrac%7B%5Chat%20p%281-%5Chat%20p%29%7D%7Bn%7D%7D%5C%5C0.03%3D1.96%5Ctimes%20%5Csqrt%7B%5Cfrac%7B0.48%281-0.48%29%7D%7Bn%7D%7D%5C%5C%28%5Cfrac%7B0.03%7D%7B1.96%7D%29%5E%7B2%7D%3D%5Cfrac%7B0.48%281-0.48%29%7D%7Bn%7D%5C%5Cn%3D1065.404%5C%5Cn%5Capprox1066)
Thus, the sample size used to compute the 95% confidence interval is 1066.