Let s = the speed of the slower train in km/hrs+10 = the speed of the faster train in km/hrLet t = time in hrs for the slower train to go 160 kmt-5 = time in hrs for faster train to go 160 km---------------Slower train:(1)
160=s.t
Faster train:(2) 160=(s+10) .(t-.5)From (1)(1) t=160/s
use the relations given in following screenshot and then use quadratic equation.
Answer:
y = x - 1
Step-by-step explanation:
Find the slope:
(-4 - (-2))/(-3 - (-1))
-2/-2 = 1
y = x + b
Plug in one of the points:
(-1,-2)
-2 = -1 + b
b = -1
y = x - 1
Answer:
4c + 15
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
15c − 4
c(15 − 4)
4c + 15
4(c + 15)
✓We were told that the customer stores parking has Total number of 4 rows,
✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c
✓ we were told that there are 15 parking spots available to employees in the store
✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)
= 4c + 15
Answer:
It is 7.5%.
Step-by-step explanation:
15 x
200 100
1500/200 = 7.5
