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elena-14-01-66 [18.8K]
4 years ago
15

Can someone help me?

Mathematics
1 answer:
mote1985 [20]4 years ago
8 0
The answer is 10 but i dont know how to show work sorry 

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Which statement describes the equation below?
Colt1911 [192]

Answer:

Abccd

Step-by-step explanation:

Hi low hin

3 0
3 years ago
What is the simplest form of the expression below? <br><br> -2x²(3x²-2x-6)
nirvana33 [79]

Answer:

   

Solution Given:

To find the simplest form we need to open bracket

-2x²(3x²-2x-6)

-2x²*3x²-2x²*(-2x) -2x²*(-6)\

-6x^{4}+4x^{3}+12x^2 is  a required answer.

7 0
2 years ago
plzzz finish 4, 5, 6, 9, 10, 11, 12, 14, and 15 you dont have to answer all but atleast anwer like 2 or 3 \( i scratched out the
nika2105 [10]

Answer:

4. -4

5. -2

6. -3

Step-by-step explanation:

4. -12 = 5r + 8

Subtract 8 from both sides;

-20 = 5r

Divide both sides by 5;

-4 = r OR r = -4

5. -6p - 3 = 9

Add 3 to both sides;

-6p = 12

Divide both sides by -6

p = -2

6. -14 = 4x - 2

Add 2 to both sides;

-12 = 4x

Divide both sides by 4;

-3 = x OR x = -3

8 0
3 years ago
Select the two values of x that are roots of this equation.
makkiz [27]

Answer:

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

Step-by-step explanation:

<u>Given </u><u>:</u><u>-</u><u> </u>

  • A quadratic equation is given to us.
  • The equation is 2x² + 7x +6=0

And we need to find out the roots of the given equation. We can use the middle term splitting method to find out the roots as ,

<u>Given </u><u>equation</u><u> </u><u>:</u><u>-</u>

\implies 2x^2 + 7x +6=0

Step 1: <u>Find</u><u> out</u><u> the</u><u> </u><u>factors</u><u> </u><u>of </u><u>1</u><u>2</u><u> </u><u>:</u><u>-</u><u> </u>

We will choose the two factors such that their sum equals to the coefficient of x i.e. 7 .The factors are , 1×12 , 2×6 , 3×4 .

  • And 3 + 4 = 7. So we will break the middle term into 3x and 4x .

Step 2 :<u> Breaking</u><u> the</u><u> </u><u>middle</u><u> term</u><u> </u><u>:</u><u>-</u><u> </u>

\implies 2x^2 + 3x+4x +6=0

Step 3: <u>Take </u><u>out </u><u>common</u><u> </u><u>from </u><u>terms </u><u>:</u><u>-</u>

\implies x(2x + 3) +2(2x +3)=0

\implies ( x +2)(2x+3)=0

Step 4 : <u>Equate </u><u>them </u><u>with </u><u>0</u><u> </u><u>:</u><u>-</u><u> </u>

\implies x = (-2) \qquad or\qquad x = \dfrac{-3}{2}

<u>Hence </u><u>the</u><u> </u><u>correct</u><u> </u><u>options </u><u>are </u><u>C </u><u>and </u><u>D </u><u>.</u>

5 0
3 years ago
Which expression is a factor of x^2 + 2x – 15?​
Ksju [112]
To factor this you need values that add up to 2 and multiply to -15

So you get 5,-3 then you put it into your equation for you b value

X^2+5x-3x-15

Then you can factor by grouping

X(x+5)-3(x+5)

So your factors are

(X+5)(x-3)
7 0
3 years ago
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