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nexus9112 [7]
3 years ago
7

What does "opposite semi-planes of segment" mean?

Mathematics
1 answer:
alexdok [17]3 years ago
4 0

Answer:

opposite half-planes – the two half-planes that are separated by a particular line of the plane. If points Y and Z are in opposite half-planes, the segment joining them must intersect the edge.

Step-by-step explanation:

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Consider the two groups listed below. Which statement describes the sets?
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The answer is d as for any given length you could have any given volume by altering the cross sectional area of the pool and vice versa
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3 years ago
Which function is linear?
Brut [27]

Answer:

f(x)=13x[+4. that one is the Correct answer. I hope it help.

5 0
2 years ago
Someone pls help:( I can’t
max2010maxim [7]

Answer:

x = 8 is the answer :)

Step-by-step explanation:

Slope(m) = -2/5

slope is passing through the points: (x,1) and (3,3)

m=\frac{y_2-y_1}{x_2-x_1}

m = \frac{3-1}{3-x}

m=\frac{2}{3-x}

-\frac{2}{5} =\frac{2}{3-x}

-2(3 - x) = 2 × 5

-6 + 2x = 10

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x = 8

Hopefully, this answer helped :)

8 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided.
rodikova [14]

Answer:

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

Step-by-step explanation:

f(x) = 9x³ + 2x² - 5x + 4; g(x)=5x³ -7x + 4

Step 1. Calculate the difference between the functions

(a) Write the two functions, one above the other, in decreasing order of exponents.

ƒ(x) = 9x³ + 2x² - 5x + 4

g(x) = 5x³           - 7x + 4

(b) Create a subtraction problem using the two functions

        ƒ(x) =    9x³ + 2x² - 5x + 4

      -g(x) =  <u>-(5x³           - 7x + 4) </u>

ƒ(x) -g(x)=

(c). Subtract terms with the same exponent of x

        ƒ(x)   =    9x³ + 2x² - 5x + 4

      -g(x)  =   <u>-(5x³          -  7x + 4) </u>

ƒ(x) -g(x) =      4x³ + 2x² + 2x

Step 2. Factor the expression

y = 4x³ + 2x² + 2x

Factor 2x from each term

y = 2x(2x² + x + 1)

\boxed{f(x) - g(x) = 2x(2x^{2} + x + 1)}

5 0
2 years ago
Given the function f(x)= 14x^2 + 5x - 1 answer the question if you could change the 14 to any other number, but the rest has to
polet [3.4K]
This is a polynomial of degree 2, and remember that complex roots always come in pairs; therefore, in a second degree polynomial you can only have 0 real roots and 2 complex roots, or 2 real roots and 0 complex roots. There is no way you can have 1 real root and 1 complex root because, as stated before, complex (non-real) roots always come in pairs; so the only way of having 1 real root is dumping the polynomial of degree 2 (14 x^{2}) by changing the 14 to 0. That way we'll left with f(x)=5x-1 which only has one real root:
0=5x-1
5x=1
x= \frac{1}{5}

7 0
3 years ago
Read 2 more answers
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