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Rus_ich [418]
2 years ago
14

Brainly is full of braindead bots. True or False?

Mathematics
2 answers:
kkurt [141]2 years ago
4 0

Answer:True

Steby-step explanation:

Anton [14]2 years ago
3 0

Answer:

False

Step-by-step explanation:

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PLEADSE HELP ILL GIVE BARINLIESDT
Vlada [557]

Answer:

non-proportional's with positive y intercept are:

y=2.5x-7

y=-5x-8

proportional's with positive y intercept are:

y=1.2x

y=-10x

y=7x/8+1

7 0
2 years ago
A large pool of adults earning their first driver’s license includes 50% low-risk drivers, 30% moderate-risk drivers, and 20% hi
Mamont248 [21]

Answer:

The probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

Step-by-step explanation:

Denote the different kinds of drivers as follows:

L = low-risk drivers

M = moderate-risk drivers

H = high-risk drivers

The information provided is:

P (L) = 0.50

P (M) = 0.30

P (H) = 0.20

Now, it given that the insurance company writes four new policies for adults earning their first driver’s license.

The combination of 4 new drivers that satisfy the condition that there are at least two more high-risk drivers than low-risk drivers is:

S = {HHHH, HHHL, HHHM, HHMM}

Compute the probability of the combination {HHHH} as follows:

P (HHHH) = [P (H)]⁴

                = [0.20]⁴

                = 0.0016

Compute the probability of the combination {HHHL} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (L)

               = 4 × (0.20)³ × 0.50

               = 0.016

Compute the probability of the combination {HHHM} as follows:

P (HHHL) = {4\choose 1} × [P (H)]³ × P (M)

               = 4 × (0.20)³ × 0.30

               = 0.0096

Compute the probability of the combination {HHMM} as follows:

P (HHMM) = {4\choose 2} × [P (H)]² × [P (M)]²

                 = 6 × (0.20)² × (0.30)²

                 = 0.0216

Then the probability that these four will contain at least two more high-risk drivers than low-risk drivers is:

P (at least two more H than L) = P (HHHH) + P (HHHL) + P (HHHM)

                                                            + P (HHMM)

                                                  = 0.0016 + 0.016 + 0.0096 + 0.0216

                                                  = 0.0488

Thus, the probability that these four will contain at least two more high-risk drivers than low-risk drivers is 0.0488.

6 0
3 years ago
The sum of two consecutive even numbers is 18.find the numbers​
vovikov84 [41]

Answer:

Numbers are 8  and  10

Step-by-step explanation:

    10 + 8 = 18

8 0
2 years ago
Dawn Dough and Dale earned different amounts $9.35,$8.52,and$8.25 dale and Doug earned about $9.00 Dawn earned exactly $1.10less
Zielflug [23.3K]

We know that the amounts earned by Dawn, Doug and Dale are from the list of numbers: $9.35, $8.52 and $8.25

We also know that Dale and Doug earned close to $9.00

And that Dawn earned $1.10 less than Dale

Let the amount earned by Dale be x

⇒ Amount earned by Dawn is x - 1.1

If we notice the list of numbers, we see that $9.35 and $8.25 differ by $1.1

Hence, Dale earned $9.35 and Dawn earned $8.25

We are now left with $8.52, which should be the amount earned by Doug. This is correct, since we also know that Doug earned close to $9.

Hence, the amounts earned are:

Dale: $9.35

Doug: $8.52

Dawn: $8.25

8 0
3 years ago
3x+y=4<br> 2x+y=5<br> solve using linear combination
Advocard [28]
Idk what linear combination is but you can solve this way:
3x+y=4
-2x-y=-5
x=-1
3(-1)+y=4
-3+y=4
y=7
So x=-1 and y=7
3 0
2 years ago
Read 2 more answers
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