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vivado [14]
3 years ago
6

H - 4 = k solve for(j) ——- j

Mathematics
1 answer:
Pavlova-9 [17]3 years ago
7 0

Answer:no

Step-by-step explanation:

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Totsakan spent $36.54 on envelopes. If they cost 4.06/box how many boxes did her buy?
Ivahew [28]
9 because you divide 36.54 by 4.06 i’m pretty sure
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3 years ago
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Graph the inequality y>x-2
Anna35 [415]

Answer: 2

Step-by-step explanation:

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3 years ago
Past records indicate that the probability of online retail orders that turn out to be fraudulent is 0.08. Suppose that, on a gi
Sunny_sXe [5.5K]

Answer:

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

Step-by-step explanation:

We can model this with a binomial random variable, with sample size n=20 and probability of success p=0.08.

The probability of k online retail orders that turn out to be fraudulent in the sample is:

P(x=k)=\dbinom{n}{k}p^k(1-p)^{n-k}=\dbinom{20}{k}\cdot0.08^k\cdot0.92^{20-k}

We have to calculate the probability that 2 or more online retail orders that turn out to be fraudulent. This can be calculated as:

P(x\geq2)=1-[P(x=0)+P(x=1)]\\\\\\P(x=0)=\dbinom{20}{0}\cdot0.08^{0}\cdot0.92^{20}=1\cdot1\cdot0.189=0.189\\\\\\P(x=1)=\dbinom{20}{1}\cdot0.08^{1}\cdot0.92^{19}=20\cdot0.08\cdot0.205=0.328\\\\\\\\P(x\geq2)=1-[0.189+0.328]\\\\P(x\geq2)=1-0.517=0.483

The probability that there are 2 or more fraudulent online retail orders in the sample is 0.483.

5 0
3 years ago
PLS HELPPPPP THANK UUU
Julli [10]

C. x=3/2 y=1/2

Hope this helps!

3 0
2 years ago
A manager at the bookstore must arrange a collection of 231 books for display. The manager decides to use a combination of 15 sh
Kitty [74]

Answer:

6 tables.

Step-by-step explanation:

If he has 15 shelves, we can put the overall number of books off to the side for a moment. First calculate how many books he COULD put onto shelves. This would be 7*15, since each of fifteen shelves can hold 7 books. Counting by fifteens or using a calculator allows us to see that the shelves can hold 105 books.

Going back to the original number of books, we subtract 105 from the original value. The equation at this point is 231 - 105. The result is 126 books left to put on top of tables. But we're not done yet!

Since a table can hold 25 books, we need to divide the remaining number of books by 25. That would be 126/25. Doing this gives us 5 tables we would need, plus one book let over. Since we've run out of shelves, we MUST use another table just for the final book. That's 5+1, or 6 tables. Let's not forget to label our answer.

6 0
3 years ago
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