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Fed [463]
3 years ago
14

A student had to multiply 328 x 41. The student’s answer was 4,598. Use estimation to explain why this answer is not reasonable

Mathematics
2 answers:
storchak [24]3 years ago
5 0
With a number of 328×41 and coming up with a answer of nearly 5,000 is not reasonable because just estimating it 300×10 is 3,000 so times that by 4 is 12,000. 
ololo11 [35]3 years ago
5 0
Its not reasonable, here is why.

Grab a sheet of paper and follow along, write 328 x 41 and put 328 on top of 41.
multiply 8 x 1
multiply 2 x 1
multiply 3 x 1
multiply 8 x 4 which is 32
multiply 2 x 4 which is 8
multiply 3 x 4 which is 12
bring down the carry digit of 1
add 328 + 13120 which is 13448
or multiply 328 x 41 and u get 13448


The answer is not reasonable because its not the correct solution.
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Answer:

We failed to reject H₀

Z > -1.645

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Step-by-step explanation:

Set up hypotheses:

Null hypotheses = H₀: p = 0.40

Alternate hypotheses = H₁: p < 0.40

Determine the level of significance and Z-score:

Given level of significance = 1% = 0.01

Since it is a lower tailed test,

Z-score = -2.33 (lower tailed)

Determine type of test:

Since the alternate hypothesis states that less than 40% of U.S. cell phone owners use their phone for most of their online browsing, therefore we will use a lower tailed test.

Select the test statistic:  

Since the sample size is quite large (n > 30) therefore, we will use Z-distribution.

Set up decision rule:

Since it is a lower tailed test, using a Z statistic at a significance level of 1%

We Reject H₀ if Z < -1.645

We Reject H₀ if p ≤ α

Compute the test statistic:

$ Z =  \frac{\hat{p} - p}{ \sqrt{\frac{p(1-p)}{n} }}  $

$ Z =  \frac{0.31 - 0.40}{ \sqrt{\frac{0.40(1-0.40)}{100} }}  $

$ Z =  \frac{- 0.09}{ 0.048989 }  $

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From the z-table, the p-value corresponding to the test statistic -1.84 is

p = 0.03288

Conclusion:

We failed to reject H₀

Z > -1.645

-1.84 > -1.645

We failed to reject H₀

p >  α

0.03 > 0.01

We do not have significant evidence at a 1% significance level to claim that less than 40% of U.S. cell phone owners use their phones for most of their online browsing.

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