3 years ago

Four equivalent forms of a quadratic function are given. Which form displays the zeros of function h?

Mathematics

1 answer:

Vedmedyk [2.9K]3 years ago

8 0

The Answer is : C.) h(x) = -4(x − 2)(x + 2)

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Given: Base ∠BAC and ∠ACB are congruent. Prove: ΔABC is an isosceles triangle. When completed (fill in the blanks), the followin

astra-53 [7]

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ASHA 777 [7]

The blank space is 4.25

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3 years ago

hudson pick 1 1/4 baskets of apple suzy pick 2 basket of apple how muck more basket apple did suzy pick than hudson.

Vinvika [58]

Answer:

3/4

Step-by-step explanation:

Hudson = 1 1/4 baskets

Suzy = 2 baskets

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Suzy - Hudson

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2 - 5/4

L. C. M = 4

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3 years ago

Need help on C. And anyone that knows this can u plz help

Neporo4naja [7]

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3 years ago

Write an equivalent series with the index of summation beginning at n = 1. ∞ (−1)n + 1(n + 1)xn n = 0

kkurt [141]

Looks like the starting series is

$\displaystyle\sum_{n=0}^\infty\left((-1)^n+1\right)(n+1)x^n$

Note the degree of the first few terms in the series, for $n=0,1,2$ , are $x^0,x^1,x^2$ , and so on.

So if the series were to start at $n=1$ , we would need to preserve that pattern, and we do that by replacing $n$ with $n-1$ :

$\displaystyle\sum_{n=1}^\infty\left((-1)^{n-1}+1\right)(n-1+1)x^{n-1}$

Simplifying a bit, we end up with

$\displaystyle\sum_{n=1}^\infty\left(1-(-1)^n\right)nx^{n-1}$

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3 years ago