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3 years ago

Evaluate 2^-4 TOOOOOOOOOOONGAAAAAAAAAAAAAA

Mathematics

2 answers:

Lerok [7]3 years ago

8 0

Answer:

1/16

Step-by-step explanation:

2 ^ -4

The negative puts the number in the denominator

1 / 2^4

1/16

Usimov [2.4K]3 years ago

4 0

The answer is 1/6 because it is

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spayn [35]

Answer:

A) f^-1(x)=(x-8)^3+2

Step-by-step explanation:

To find the function inverse, switch the x with y and solve for y.

$y=\sqrt[3]{x-2}+8 \\\\x=\sqrt[3]{y-2}+8\\\\(x-8)^3 = y-2\\\\ (x-8)^3 + 2 = y$

5 0

3 years ago

Gerald recorded the gains and losses for each play on the football field. Gains were marked with a + and losses with a –. Play 1

Vedmedyk [2.9K]

Answer:

Play 3

Step-by-step explanation:

Given:

$\left\begin{array}{ccccc}{Play}&{1}&{2}&{3}&{4}&{Yards}&{+4}&{-6}&{-2}&{+3}\end{array}\right$

Required [Missing from the question]:

Determine the play with the least change in yard?

To do this, we ignore the sign in front of each yard before we analyze.

So, we have:

Play 1 has a change of 4

Play 2 has 6

Play 3 has 2

Play 4 has 3

<em>From the above analysis, play has the least (which is 2)</em>

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2 years ago

You are buying boxes of cookies at a bakery. Each box of cookies costs 4 dollars. In the equation below, c represents the number

Yuliya22 [10]

What the answer you want to find out ?

7 0

3 years ago

Reuben says, "two days ago i was 20 years old. later next year, i will be 23 years old." how is this possible?

Aneli [31]

Let us always base on the present age. We denote this by x. Now, the age he had 2 years ago would then be denoted as (x-2). Let's equate this to 20 years old.

x - 2 = 20
x = 20 + 2
x = 22 years old
He should be 22 years old now.

Let's check the other condition. After 1 year, his age should be (x+1). Let's equate this to 23 years old.

x + 1 = 23
x = 23 - 1
x = 22

Thus, this is possible if Reuben is 22 years old as of the present.

7 0

3 years ago

Solve pleasee<br><br> x(7-x)>8

maks197457 [2]

I forgot about this one!! I lbew but I lost it!! Sorry :(

3 0

3 years ago