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MrRissso [65]
2 years ago
13

Ratios for 42 and 54

Mathematics
2 answers:
KiRa [710]2 years ago
8 0

Answer:

The ratio is easy to find!

Ratios are:

42:54

42 to 54

42/53

Step-by-step explanation:

            May I have brainliest I'm trying to level up!

                        </3 PureBeauty

seropon [69]2 years ago
3 0

Answer:30 and 7

Step-by-step explanation:

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How many different committees can be formed from 11
Vikki [24]

Answer:

2 Committees

Step-by-step explanation:

2 Committees and 3/4 of a committee

There are only 11 teachers so that means only 2 committees can be filled with 4 teachers if that is the max amount per committee.

There are more than enough students so no need to worry on them.

11 divided by 4 = 2.75

5 0
3 years ago
Pleaseeeeee helpppppppp i will mark brainlest
irga5000 [103]

Answer:

B

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
SOLVE THE EQUATION FOR Y
max2010maxim [7]
(4)\ -6x + y = 11\ \ \ \Rightarrow\ \ \ y=6x+11\\\\(5)\ \ 8x + 2y = 10\ \ \ \Rightarrow\ \ \ 2y=-8x+10\ \ \ \Rightarrow\ \ \ y=-4x+5\\\\(6)\ \  6x - 3y = -9\ \ \ \Rightarrow\ \ \ -3y=-6x-9\ \ \ \Rightarrow\ \ \ y=2x+3\\\\(7)\ \  -4x + 2y = 16\ \ \ \Rightarrow\ \ \ 2y=4x+16\ \ \ \Rightarrow\ \ \ y=2x+8\\\\&#10;(8)\ \  10x - 5y = 25\ \ \ \Rightarrow\ \ \ -5y=-10x+25\ \ \ \Rightarrow\ \ \ y=2x-5\\\\(9)\ \  3x + 2y = -8\ \ \ \Rightarrow\ \ \ 2y=-3x-8\ \ \ \Rightarrow\ \ \ y=-1.5x-4&#10;
6 0
3 years ago
15 - (-3) - 4<br><br> -16<br><br> 22<br><br> -8<br><br> 14
uranmaximum [27]
In this equation, you have to treat the number in the bracket first on the basis of BODMAS
15 - [-3]- 4
Note that when two minuses come together the product is a plus sign.
15 +3 - 4
You have to add before you subract
18 - 4 =14
Therefore, 15- [-3] - 4 = 14.
8 0
3 years ago
This question is from the similarity chapter. It would be really kind of you if you would answer this question.
katen-ka-za [31]

Answer:

a) 1650 m

b) 1677.05 m

Step-by-step explanation:

Hi there!

<u>1) Determine what is required for the answers</u>

For part A, we're asked for solve for the horizontal distance in which the road will rise 300 m. In other words, we're solving for the distance from point A to point C, point C being the third vertex of the triangle.

For part B, we're asked to solve for the length of the road, or the length of AB.

<u>2) Prove similarity</u>

In the diagram, we can see that there are two similar triangles: Triangle AXY and ABC (please refer to the image attached).

How do we know they're similar?

  1. Angles AYX and ACB are corresponding and they both measure 90 degrees
  2. Both triangles share angle A

Therefore, the two triangles are similar because of AA~ (angle-angle similarity).

<u>3) Solve for part A</u>

Recall that we need to find the length of AC.

First, set up a proportion. XY corresponds to BC and AY corresponds to AC:

\frac{XY}{BC}=\frac{AY}{AC}

Plug in known values

\frac{2}{300}=\frac{11}{AC}

Cross-multiply

2AC=11*300\\2AC=3300\\AC=1650

Therefore, the road will rise 300 m over a horizontal distance of 1650 m.

<u>4) Solve for part B</u>

To find the length of AB, we can use the Pythagorean theorem:

a^2+b^2=c^2 where c is the hypotenuse of a right triangle and a and b are the other sides

Plug in 300 and 1650 as the legs (we are solving for the longest side)

300^2+1650^2=c^2\\300^2+1650^2=c^2\\2812500=c^2\\1677.05=c

Therefore, the length of the road is approximately 1677.05 m.

I hope this helps!

3 0
2 years ago
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