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3 years ago

A set of equations is given below:

Mathematics

1 answer:

TEA [102]3 years ago

6 0

The 3rd selection is appropriate.

.. 5b +1 = a = 3b +5
by the transitive property of equality,
.. 5b +1 = 3b +5

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Kira needs 3,000 milligrams of zinc for a science experiment. Which expression can be used to determine how many grams of zinc s

harina [27]

Answer: 3,000 divided by a thousand

Step-by-step explanation: 1,000 milligrams equal one gram so you divide the number of milligrams by 1,000 to find out the number of grams.

8 0

3 years ago

Is 3/8 equal to 4/10?

BaLLatris [955]

8ths are divided by 12.5 so 3 * 12.5 is 37.5
10ths are divided by 10 so 4 * 10 is 40

3/8 is < / = 4/10

3 0

2 years ago

If Greg Mills is paid 12¢ per unit and produces 170, 165, 149, 157, and 181 units in the 5 days of one week, what is his pay?

Leya [2.2K]

get the total units made:

170 + 165 + 149 + 157 + 181 = 822 units.

Multiply by pay:

822 x 0.12 = $98.64

6 0

3 years ago

The median of a probability distribution can be defined as the number m such that Upper P (Upper X less than or equals m )equals

Alexxandr [17]

Answer:

tex]M=\beta ln(2)[/tex]

Step-by-step explanation:

Previous concepts

The exponential distribution is "the probability distribution of the time between events in a Poisson process (a process in which events occur continuously and independently at a constant average rate).

Solution to the problem

For this case we can use the following Theorem:

"If X is a continuos random variable of the exponential distribution with parameter $\beta$ for some $\beta \in R >0$ "

Then the median of X is $\beta ln (2)$

Proof

Let M the median for the random variable X.

From the definition for the exponential distribution we know the denisty function of X is given by:

$f_X (x) = \frac{1}{\beta} e^{-\frac{x}{\beta}}$

Since we need the median we can put this equation:

$P(X$

If we evaluate the integral we got this:

$\frac{1}{\beta} \int_0^M e^{- \frac{x}{\beta}}dx =\frac{1}{\beta} [-\beta e^{-\frac{x}{\beta}}] \Big|_0^M$

And that's equal to:

$1/2 = 1 -e^{- \frac{M}{\beta}}$

And if we solve for M we got:

$1-e^{- \frac{M}{\beta}} = \frac{1}{2}$

$e^{- \frac{M}{\beta}}=\frac{1}{2}$

If we apply natural log on both sides we got:

$-\frac{M}{\beta}=ln(1/2)$

And then $M=\beta ln(2)$

5 0

2 years ago

In a bag there are eight red marbles, twelve blue marbles, and four green marbles. What is the probability that you will draw a

weeeeeb [17]

8+12+4= 24

This is the total amount of marbles. You’ll divide the green marbles by the total amount since you want the probability of green marbles.

4/24= .16 or 16% possibikity

7 0

2 years ago