AAS Postulate
It is given that CE = BD so we know "S" (representing side) has to be in the three letter postulate.
It is also given that angle DBA and angle CEA are right angles, so therefore they are congruent. Now we know that an "A" must also be in the postulate.
Lastly, we know that the triangles have a second angle, EAB, in common because they share it overlappingly. So there must be another "A" in the postulate.
Now we need to look at the order in which it is presented. The order follows Angle, Angle, Side so the postulate must be the AAS postulate. Hope this helps!
Answer:
a,e,f
Step-by-step explanation:
a. 6p+6
b.12p
c.6p
d.5p+6
e.6p+6
f.6p+6
Answer:
see the attached picture please
Answer:
0.00118063754
is right...
Step-by-step explanation:
<span><span>1.
If we get an odd number first (probability 5/10 = 1/2), then the only way to get a number greater than 9 is the 10 (probability 1/9, since only 9 papers remain). This gives 1/2 * 1/9 = 1/18.</span></span><span><span>
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</span></span><span><span>2.
We would expect that P(2 white cards) = P(1 white card)*P(2nd white card given 1 white card).</span></span><span><span /></span><span><span>This gives the equation 14/95 = 2/5 * x<span>
</span></span></span><span><span><span>Solving for x gives x = 7/19.</span></span></span><span><span>
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</span></span><span><span>3. There are a total of 4 favorable results: 1, 4, 5, 6. Out of the 6 possibilities, this is a probability of 4/6 = 2/3.</span></span>
