Question

Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2). 25 POINTS

Answer 1

• (-6,4)
• (0,2)

$\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}$

Answer 2

Answer:

• 3

Step-by-step explanation:

Line through ( – 6, 4) and (0,2) has a slope:

• m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

The line perpendicular to this has a slope, negative-reciprocal to this:

• m₂ = -1/m₁ = -1 /(-1/3) = 3