Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2). 25 POINTS

Mathematics

2 answers:

yan [13]3 years ago

7 0

(-6,4)
(0,2)

$\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}$

Ainat [17]3 years ago

5 0

Answer:

Step-by-step explanation:

<u>Line through ( – 6, 4) and (0,2) has a slope:</u>

m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

<u>The line perpendicular to this has a slope, negative-reciprocal to this:</u>

m₂ = -1/m₁ = -1 /(-1/3) = 3

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A local bagel shop produces two products: bagels (B) and croissants (C). Each bagel requires 6 ounces of flour, 1 gram of yeast,

KengaRu [80]

Answer:

see below

Step-by-step explanation:

If we let X represent the number of bagels produced, and Y the number of croissants, then we want ...

(a) Max Profit = 20X +30Y

(b) Subject to ...

6X +3Y ≤ 6600 . . . . . . available flour

X + Y ≤ 1400 . . . . . . . . available yeast

2X +4Y ≤ 4800 . . . . . . available sugar

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Production of 400 bagels and 1000 croissants will produce a maximum profit of $380.

In the attached graph, we have shaded the areas that are NOT part of the solution set. (X and Y less than 0 are also not part of the solution set, but are left unshaded.) This approach can sometimes make the solution space easier to understand, since it is white.

The vertex of the solution space that moves the profit function farthest from the origin is the one we are seeking. The point that does that is (X, Y) = (400, 1000).