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soldier1979 [14.2K]
3 years ago
5

Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2). 25 POINTS

Mathematics
2 answers:
yan [13]3 years ago
7 0
  • (-6,4)
  • (0,2)

\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}

\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}

\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}

\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}

Ainat [17]3 years ago
5 0

Answer:

  • 3

Step-by-step explanation:

<u>Line through ( – 6, 4) and (0,2) has a slope:</u>

  • m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

<u>The line perpendicular to this has a slope, negative-reciprocal to this:</u>

  • m₂ = -1/m₁ = -1 /(-1/3) = 3
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