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3 years ago

Find the slope of any line perpendicular to the line through ( – 6, 4) and (0,2). 25 POINTS

Mathematics

2 answers:

yan [13]3 years ago

7 0

(-6,4)
(0,2)

$\\ \bull\tt\dashrightarrow Slope=\dfrac{y_2-y_1}{x_2-x_1}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{2-4}{0+6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-2}{6}$

$\\ \bull\tt\dashrightarrow Slope=\dfrac{-1}{3}$

Ainat [17]3 years ago

5 0

Answer:

Step-by-step explanation:

Line through ( – 6, 4) and (0,2) has a slope:

m₁ = (2 - 4)/(0 - (-6)) = -2/6 = -1/3

The line perpendicular to this has a slope, negative-reciprocal to this:

m₂ = -1/m₁ = -1 /(-1/3) = 3

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Seeds are often treated with fungicides to protect them in poor-draining, wet environments. A small-scale trial, involving six t

alukav5142 [94]

Answer:

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Step-by-step explanation:

The plants were chosen without replacement, which means that the hypergeometric distribution is used to solve this question.

Hypergeometric distribution:

The probability of x successes is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of successes.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

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In this question:

6 + 6 = 12 seeds, which means that $N = 12$

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Five sprouted, which means that $n = 5$

What is the probability that all five plants emerged from treated seeds?

This is P(X = 5). So

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

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