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nikitadnepr [17]
3 years ago
9

Please answer and explain how you did it.

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0

Refer to the attached image.

Given: m \angle A = 65^\circ and measure of exterior angle at C = 117^\circ.

We have to determine the measure of angle B and angle BCA.

By applying exterior angle property of the triangle which states:

"An exterior angle of a triangle is equal to the sum of the opposite interior angles".

So, exterior angle C = m \angle A + m \angle B

117^\circ = 65^\circ+ m \angle B

m \angle B = 52^\circ

Now, applying angle sum property in triangle ABC which states:

"The sum of all the angles of a triangle is 180 degrees".

m \angle A + m \angle B + m \angle BCA = 180^\circ

65^\circ + 52^\circ + m \angle BCA = 180^\circ

117^\circ + m \angle BCA = 180^\circ

m \angle BCA = 180^\circ - 117^\circ

m \angle BCA =63^\circ

Therefore, the measure of m \angle B = 52^\circ and m \angle BCA =63^\circ.

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