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Kobotan [32]
3 years ago
15

Công ty A&T có thông tin về hàng tồn kho năm 20X0 như sau: - Giá trị hàng tồn kho: 6.000 triệu đồng (loại 1 là 2.000 triệu đ

ồng, loại 2 là 4.000 triệu đồng). Hai loại hàng tồn kho này không cùng bản chất. Số lượng hàng tồn kho loại 1 dùng cho các hợp đồng bản hàng đã ký lớn hơn số lượng hàng tồn kho loại 1 hiện tại. -Cuối kỳ kế toán công ty đánh giá lại hàng tồn kho với các thông tin đáng tin cậy như sau: + giá bán ước tính của hàng tồn kho loại 1 là 2.000 triệu đồng, loại 2 là 4.300 triệu đồng + chi phi bán hàng, ước tính của loại 1 là 40 triệu đồng, loại 2 là 30 triệu đồng. Yêu cầu: Công ty A ghi nhận các nội dung kinh tế trên như thế nào theo chuẩn mực báo cáo tài chính quốc tế giá trị hàng tồn kho, giá trị thuần có thể thực hiện được hoặc dự phòng)?
Mathematics
1 answer:
iragen [17]3 years ago
6 0
Oh my god why so long
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If the integers have the same absolute value ... they're the same number
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Example:    (plus) 927 added to (negative) 927  =  zero


If the integers have different absolute values ... they're different numbers with different
signs ... then their sum has the same sign as the one with the bigger absolute value.

Examples:

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3 years ago
A researcher tests five individuals who have seen paid political ads about a particular issue. These individuals take a multiple
devlian [24]

Answer:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

Step-by-step explanation:

Information given

48, 41, 40, 51, and 50

The sample mean and deviation can be calculated with these formulas:

\bar X= \frac{\sum_{i=1}^n X_i}{n}

s =\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

\bar X=46 represent the mean height for the sample  

s=5.148 represent the sample standard deviation

n=5 sample size  

\mu_o =40 represent the value that we want to test

\alpha=0.05 represent the significance level for the hypothesis test.  

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to test if the true mean for this case is equal to 40, the system of hypothesis would be:  

Null hypothesis:\mu = 40  

Alternative hypothesis:\mu \neq 40  

The statistic is given by:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Replacing we got:

t=\frac{46-40}{\frac{5.148}{\sqrt{5}}}=2.606    

The degrees of freedom are given by:

df=n-1=5-1=4  

The p value wuld be given by:

p_v =2*P(t_{(4)}>2.606)=0.060  

For this case the p value is higher than the significance level so then we can conclude that the true mean is not significantly different from 40

The distribution with the critical values are in the figure attached

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Answer:

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4x=172

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