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bazaltina [42]
3 years ago
8

x^2+{a/a+b + a+b/a}x+1=0 solve for x please solve and i will mark you as the brainliest..its urgent i need to confirm my answer.

..
Mathematics
1 answer:
zepelin [54]3 years ago
6 0

Answer:

x^2 + {a/(a + b) + (a + b)/a}x + 1 = 0

Delta =  {a/(a + b) + (a + b)/a}^2 - 4

         =  {a/(a + b)}^2 + {(a + b)/a}^2 + 2 - 4

         =  {a/(a + b)}^2 + {(a + b)/a}^2  - 2

         =  {a/(a + b) - (a + b)/a}^2

If a is not equal to zero and a is not equal to -b => delta is always larger than 0

=>  Solution 1 =  - [ {a/(a + b) + (a + b)/a} + |{a/(a + b) - (a + b)/a}| ]/2

=>  Solution 2 = - [ {a/(a + b) + (a + b)/a} - |{a/(a + b) - (a + b)/a}| ]/2

Hope this helps!

:)

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Lady_Fox [76]

Answer:

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

What is an equation?

An equation is an expression that shows the relationship between two or more variables and numbers.

Let x represent the amount the artist can receive for the goods, hence:

|x - 250| = 25

x - 250 = 25 or -(x - 250) = 25

x = 275 or x = 225

The absolute value equation to represent the scenario is |x - 250| = 25. Also, the minimum amounts and maximum amounts that the artist received for her products is $225 and $275 respectively.

5 0
2 years ago
Evaluate 33/5 - 1/10
azamat

Answer:

\large\boxed{\dfrac{13}{2}=6\dfrac{1}{2}=6.5}

Step-by-step explanation:

We have the different denominators.

The common denominator is 10.

\dfrac{33}{5}=\dfrac{33\cdot2}{5\cdot2}=\dfrac{66}{10}

We can subtract these fractions now.

\dfrac{33}{5}-\dfrac{1}{10}=\dfrac{66}{10}-\dfrac{1}{10}=\dfrac{66-1}{10}=\dfrac{65:5}{10:5}=\dfrac{13}{2}\\\\\dfrac{13}{2}=\dfrac{12+1}{2}=6\dfrac{1}{2}

3 0
3 years ago
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Dominik [7]

Answer:

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Step-by-step explanation:

The minimum value is the minimum y-value a function includes. In this case, since you can see the function is periodic (it repeats itself <em>periodically</em>, hence periodic) and the smallest y-value the function encounters is 2.5 (doesn't go below this value), the minimum y-value is 2.5. I hope this made sense. If not, feel free to let me know.

6 0
2 years ago
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
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Hello,

h(x)'=(f(x)*g(x))'=f'(x)*g(x)+f(x)*g'(x)
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OverLord2011 [107]
The answer is P to A prime is 3 I think

Good luck!
8 0
2 years ago
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