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3 years ago

An isosceles triangle has

Mathematics

1 answer:

Mashcka [7]3 years ago

8 0

An isosceles triangle has AT LEAST 2 equal length sides.

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Answer: E

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Which number is an integer? 6 4.2 3/4 5 1/2

stellarik [79]

Answer:

5, 6

Step-by-step explanation :

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Graph: y < + y -2 2 -2 Draw Click or tap the graph to plot a point.

ICE Princess25 [194]

Answer:

I dunno what you wrote at the top, but I solved the picture

Step-by-step explanation:

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3 years ago

6. Solve the following equation for x. Show each step. 5x + 2 = 3x + 4(2x - 1)

monitta

Answer:

x=1

Step-by-step explanation:

5x + 2 = 3x + 4(2x - 1)

Distribute the 4

5x + 2 = 3x + 8x - 4

Combine like terms

5x + 2 = 11x - 4

Subtract 5x from each side

5x -5x + 2 = 11x - 5x - 4

2 = 6x-4

Add 4 to each side

2+4 = 6x-4+4

6 = 6x

Divide each side by 6

6/6 =6x/6

1= x

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3 years ago

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Find, correct to four decimal places, the length of the curve of intersection of the cylinder 4x2 1 y2 − 4 and the plane x 1 y 1

charle [14.2K]

Answer- Length of the curve of intersection is 13.5191 sq.units

Solution-

As the equation of the cylinder is in rectangular for, so we have to convert it into parametric form with

x = cos t, y = 2 sin t (∵ 4x² + y² = 4 ⇒ 4cos²t + 4sin²t = 4, then it will satisfy the equation)

Then, substituting these values in the plane equation to get the z parameter,

cos t + 2sin t + z = 2

⇒ z = 2 - cos t - 2sin t

∴ $\frac{dx}{dt} = -\sin t$

$\frac{dy}{dt} = 2 \cos t$

$\frac{dz}{dt} = \sin t-2cos t$

As it is a full revolution around the original cylinder is from 0 to 2π, so we have to integrate from 0 to 2π

∴ Arc length

$= \int_{0}^{2\pi}\sqrt{(\frac{dx}{dt})^{2}+(\frac{dy}{dt})^{2}+(\frac{dz}{dt})^{2}$

$=\int_{0}^{2\pi}\sqrt{(-\sin t)^{2}+(2\cos t)^{2}+(\sin t-2\cos t)^{2}$

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$

Now evaluating the integral using calculator,

$=\int_{0}^{2\pi}\sqrt{(2\sin t)^{2}+(8\cos t)^{2}-(4\sin t\cos t)$ $= 13.5191$

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3 years ago