Question

4x3y3·(3x3−7xy2+2xy−y)

Answer 1

Answer:

The simplified given expression is

$4x^3y^3.(3x^3-7xy^2+2xy-y)=12x^6y^3-28x^4y^5+8x^4y^4-4x^3y^4$

Step-by-step explanation:

Given expression is $4x^3y^3.(3x^3-7xy^2+2xy-y)$

To simplify the given expression $4x^3y^3.(3x^3-7xy^2+2xy-y)$ :

By using Distributive property a.(bx+cd)=abx+acd

$4x^3y^3.(3x^3-7xy^2+2xy-y)=(4x^3y^3).(3x^3)+(4x^3y^3).(-7xy^2)+(4x^3y^3).(2xy)+(4x^3y^3).(-y)$ (by using distributive property )

$=12x^3x^3y^3-28x^3xy^3y^2+8x^3xy^3y-4x^3y^3y$ (by distributive property) and combining the like powers

$=12x^{3+3}y^3-28x^{3+1}y^{3+2}+8x^{3+1}y^{3+1}-4x^3y^{3+1}$ ( using $a^m.a^n=a^{m+n}$ ) summing the powers

$=12x^6y^3-28x^4y^5+8x^4y^4-4x^3y^4$  ( using $a^m.a^n=a^{m+n}$ )

Therefore  $4x^3y^3.(3x^3-7xy^2+2xy-y)=12x^6y^3-28x^4y^5+8x^4y^4-4x^3y^4$

Therefore the simplified expression is $12x^6y^3-28x^4y^5+8x^4y^4-4x^3y^4$