Fractions are just unsimplified numbers. For example 5/8 is just 5 divided by 8 so 0.625. To find the percent from that you move the decimal two places to the right making it 62.5%. Hope this helps!
Not sure about the first one but the second one is option c (or -3). You just have to factor and find the solutions (so it would be -7 and 4 and then u just add them)
For question 39 the answer is c
Answer:
5b - 138
Step-by-step explanation:
Alright let's break it down.
First, you can see that each constant (5,126,7) have negatives in front of them. SO you are going to subtract each one of them.
When subtracting negatives it's basically just adding them together. How to do it is simply adding:
5 + 126 + 7
Then you get 138.
BUT, it was negative numbers. So it's actually -138.
Then bring back the 5b and your answer is:
5b - 138
Mark brainliest if you can :D
Answer:
D = L/k
Step-by-step explanation:
Since A represents the amount of litter present in grams per square meter as a function of time in years, the net rate of litter present is
dA/dt = in flow - out flow
Since litter falls at a constant rate of L grams per square meter per year, in flow = L
Since litter decays at a constant proportional rate of k per year, the total amount of litter decay per square meter per year is A × k = Ak = out flow
So,
dA/dt = in flow - out flow
dA/dt = L - Ak
Separating the variables, we have
dA/(L - Ak) = dt
Integrating, we have
∫-kdA/-k(L - Ak) = ∫dt
1/k∫-kdA/(L - Ak) = ∫dt
1/k㏑(L - Ak) = t + C
㏑(L - Ak) = kt + kC
㏑(L - Ak) = kt + C' (C' = kC)
taking exponents of both sides, we have

When t = 0, A(0) = 0 (since the forest floor is initially clear)


So, D = R - A =

when t = 0(at initial time), the initial value of D =
