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Citrus2011 [14]
3 years ago
11

Find cosine of angle a ​

Mathematics
1 answer:
Hunter-Best [27]3 years ago
6 0

Answer:

ଆପଣ ଅଧ୍ୟୟନ କରିପାରିବେ ଏବଂ ଇଣ୍ଟରନେଟ୍ ବ୍ୟବହାର କରି ଆପଣଙ୍କର ସମୟ ନଷ୍ଟ କରିପାରିବେ ନାହିଁ :)

Step-by-step explanation:

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2 years ago
Find two numbers a and b whose sum a+b is -4 and whose difference a−b is -4.
Pepsi [2]
The answer is a = -4 and b = 0.

We can solve this by looking at a system of equations using what was given

a + b = -4
a - b = -4

Then add then two equations together. 

2a = -8 ---> then divide by 2 for your a value
a = -4

You can then put that into the equation and solve for b. 

-4 + b = -4 ---> add 4 to both sides
b = 0
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3 years ago
A study finds that college students found it unpleasant to sit alone and think.1 The same article describes a second study in wh
Alisiya [41]

Answer:

Assuming a confidence level of 95%.

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

The standard error for this case is given by: SE= 0.154

(0.667-0.25) - 1.96*0.154=0.115  

(0.667-0.25) + 1.96*0.154=0.719  

And the 95% confidence interval for the difference of the two proportions would be given (0.115;0.719).  

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

p_A represent the real population proportion for brand A  

\hat p_A =\frac{12}{18}=0.667 represent the estimated proportion for male

n_A=18 is the sample size required for male

p_B represent the real population proportion for female

\hat p_B =\frac{6}{24}=0.25 represent the estimated proportion for female

n_B=24 is the sample size required for female

z represent the critical value for the margin of error  

The population proportion have the following distribution  

p \sim N(p,\sqrt{\frac{p(1-p)}{n}})  

Solution to the problem

The confidence interval for the difference of two proportions would be given by this formula  

(\hat p_A -\hat p_B) \pm z_{\alpha/2} \sqrt{\frac{\hat p_A(1-\hat p_A)}{n_A} +\frac{\hat p_B (1-\hat p_B)}{n_B}}  

Assuming a confidence level of 95%.

For the 95% confidence interval the value of \alpha=1-0.95=0.05 and \alpha/2=0.025, with that value we can find the quantile required for the interval in the normal standard distribution.  

z_{\alpha/2}=1.96  

The standard error for this case is given by: SE= 0.154

And replacing into the confidence interval formula we got:  

(0.667-0.25) - 1.96*0.154=0.115  

(0.667-0.25) + 1.96*0.154=0.719  

And the 95% confidence interval for the difference of the two proportions would be given (0.115;0.719).  

7 0
3 years ago
Please help me this teacher is going to fast for me
Brilliant_brown [7]

Answer:

the first rental

34x + 0.50y

Second

20x + 0.75y

Step-by-step explanation:

8 0
2 years ago
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