Given:
Three integers, a, b, and c, where c is a positive integer.
The product of a and b is 6.
The product of a and c is -4.
The product of b and c is -6.
To find:
The values of a,b and c.
Solution:
According to the given information:
...(i)
...(ii)
...(iii)
From (ii), we get
...(iv)
From (iii), we get
...(v)
Putting and in (i), we get
Taking square root on both sides, we get
It is given that c is a positive integer. So, it cannot be negative and the only value of c is 
.
Putting in (iv), we get
Putting in (v), we get
Therefore, the values of a,b,c are 
.
sin(x+y)=sin(x)cos(y)-cos(x)sin(y)
also, remember pythagorean rule, 
given that sin(Θ)=4/5 and cos(x)=-5/13
find sin(x) and cos(Θ)
sin(x)
cos(x)=-5/13
using pythagorean identity
(sin(x))^2+(-5/13)^2=1
sin(x)=+/- 12/13
in the 2nd quadrant, sin is positve so sin(x)=12/13
cos(Θ)
sin(Θ)=4/5
using pythagrean identity
(4/5)^2+(cos(Θ))^2=1
cos(Θ)=+/-3/5
in 1st quadrant, cos is positive
cos(Θ)=3/5
so sin(Θ+x)=sin(Θ)cos(x)+cos(Θ)sin(x)
sin(Θ+x)=(4/5)(-5/13)+(3/5)(12/13)
sin(Θ+x)=16/65
answer is 1st option
Answer:
-25
Step-by-step explanation:
You can take 10÷-⅖=-25
I'm pretty sure there are no rational numbers between 9.6 and 9.7
Answer:
D. 0.65
Step-by-step explanation:
0.05 x 5=0.25
0.01 x 5=0.05
0.07 x 5=0.35
0.25+0.05+0.35=0.65
they all must pay 0.65 each
