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yuradex [85]
3 years ago
13

1) Find the slope of the line passing through the given points (2, 120) and (1, 60).

Mathematics
1 answer:
EastWind [94]3 years ago
5 0

Answer:

1. 60. 2. -6. 3. -4/5

Step-by-step explanation:

Okay so I haven't done slope in 3 years but I used to be a god at it so please tell me if you get this right and I'm so so sorry if you get them wrong

You might be interested in
If you could help I would really appreciate it, but if not that’s fine. Thank you.
Svetradugi [14.3K]
Since 4 is between 2 & 5 you input it into the middle equation.

x=4

so the answer is 4!
7 0
3 years ago
Va rog sa ma ajutați: 420/180x54/180
MAVERICK [17]
First, you want to divide 420 by 180. Then, divide 54 by 180. Lastly, you want to multiply the answers of the two together.
                    - 
420/180= 2.3 

54/180= 0.3

2.3 * 0.3 = 0.69

*You just take it step by step. Hope I helped. :)
4 0
3 years ago
Read 2 more answers
Wich integer in the set has the greatest value (-144, -4, -3, -13)
castortr0y [4]

Answer:

the answer is -3

its just opposite to the normal when we check negative numbers.

7 0
3 years ago
Please answer number 4 please
ipn [44]

Answer:

x < -2.5

Step-by-step explanation:

N/A

8 0
3 years ago
Assume that foot lengths of women are normally distributed with a mean of 9.6 in and a standard deviation of 0.5 in.a. Find the
Makovka662 [10]

Answer:

a) 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b) 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c) 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation \frac{\sigma}{\sqrt{n}}.

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 9.6, \sigma = 0.5.

a. Find the probability that a randomly selected woman has a foot length less than 10.0 in

This probability is the pvalue of Z when X = 10.

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 9.6}{0.5}

Z = 0.8

Z = 0.8 has a pvalue of 0.7881.

So there is a 78.81% probability that a randomly selected woman has a foot length less than 10.0 in.

b. Find the probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

This is the pvalue of Z when X = 10 subtracted by the pvalue of Z when X = 8.

When X = 10, Z has a pvalue of 0.7881.

For X = 8:

Z = \frac{X - \mu}{\sigma}

Z = \frac{8 - 9.6}{0.5}

Z = -3.2

Z = -3.2 has a pvalue of 0.0007.

So there is a 0.7881 - 0.0007 = 0.7874 = 78.74% probability that a randomly selected woman has a foot length between 8.0 in and 10.0 in.

c. Find the probability that 25 women have foot lengths with a mean greater than 9.8 in.

Now we have n = 25, s = \frac{0.5}{\sqrt{25}} = 0.1.

This probability is 1 subtracted by the pvalue of Z when X = 9.8. So:

Z = \frac{X - \mu}{s}

Z = \frac{9.8 - 9.6}{0.1}

Z = 2

Z = 2 has a pvalue of 0.9772.

There is a 1-0.9772 = 0.0228 = 2.28% probability that 25 women have foot lengths with a mean greater than 9.8 in.

5 0
3 years ago
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