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vaieri [72.5K]
3 years ago
8

Solve the system of equations by substitution. What is the solution for x? 2x + y = 1 4x + 2y = −1

Mathematics
2 answers:
lapo4ka [179]3 years ago
8 0
Solve your system of equations.

2x+y=1;4x+2y=−1

Solve 2x+y=1 for y:

2x+y+−2x=1+−2x(Add -2x to both sides)

y=−2x+1

Substitute (−2x+1) for y in 4x+2y=−1:

4x+2y=−1

4x+2(−2x+1)=−1

2=−1(Simplify both sides of the equation)

2+−2=−1+−2(Add -2 to both sides)

0=−3

Answer: No solution. C)

nordsb [41]3 years ago
7 0
2x+y=1 \ \ \ \ \ \ \ \ |\times (-2) \\
4x+2y=-1 \\ \\
-4x-2y=-2 \\
\underline{4x+2y=-1 \ \ \ } \\
0=-3 \\
false \\ \\
\hbox{no solution}

The answer is C.
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Solve for b2 in A = 1/2 h(b1+b2), if A = 16, h = 4, and b1 = 3. 16= 1/2* 4(3+b2) =6+2b2 or, b2= [16-6]/2= 5
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Assuming you are referring to the area of a "trapezoid"; in which one calculates the Area, "A", as follows:
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<span> A = 1/2* h(b1+b2) ;

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               b2 = length of the other of the two bases = ? (what we want to solve                                                                                            for) ;
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Using the formula: </span>A = 1/2 h(b1+b2) ;
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 →Note: On the "right-hand side" on this equation: "(1/2)*(4) = 2 ." 
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 → 16 =   2*(3 + b2) ;  → Solve for "b2".
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 → Rewrite as: 8 = 3 + b2;
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b2= [16-6]/2= 5 ; as this is the only answer choice that has: "b2 = 5".
<span>_________________________________________

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_____________________________
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