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Lana71 [14]
3 years ago
6

Hurry!! State the domain of the glven relation.

Mathematics
1 answer:
kipiarov [429]3 years ago
3 0

Answer:

x ≤ -1

Step-by-step explanation:

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Zach spent 2/3 hour reading on Friday and 1 1/3 hours reading on Saturday. how much more time did he read on Saturday than on Fr
amid [387]
11/3 - 2/3 = 9/3 = 3 so he spent 3 more hours reading on saturday than on friday


Hope this helps!
6 0
3 years ago
1. The population of a small town has established a growth rate of 3% per year. If the
Rasek [7]

Answer:

17 years

Step-by-step explanation:

3% of 2000 = 60

3000-200 = 1000

1000 ÷ 60= 16.6666666667

Round to the nearest whole number: 17

8 0
3 years ago
Which number is a perfect square<br> 32<br> 144<br> 1000<br> 36000
galben [10]
144 is a square of 12

Hope this helps!
4 0
3 years ago
Read 2 more answers
Question 2 2.1 2.2 2.2.1 2.2.2 Determine the general solution for sin(x - 30°) = cos 2x Consider the functions f(x) = sin(x-30°)
OLEGan [10]

The general solution for the given equation is 40°+120°n.

The period of g(x) is π.

The range of f(x) is [-1, 1].

  • sin(x-30°) = cos 2x
  • sin(x-30°) = sin(90°-2x)
  • (x-30°) = (90°-2x) + 360°n
  • x + 2x =  90° + 30° + 360°n
  • 3x = 120° + 360°n
  • x = (120° + 360°n)/3
  • The general solution (x) is 40° + 120°n.
  • g(x) = cos 2x
  • The period of cos x is 2π.
  • If the multiplying factor of x is 'n', then it decreases the period by n times.
  • Here, in g(x), n is 2.
  • The period of g(x) is equal to half the period of cos x.
  • The period of g(x) = 2π/2
  • The period of g(x) is π.
  • f(x) = sin(x-30°)
  • "Sin" is a trigonometric function which has a range from -1 to 1.

To learn more about  period, visit :

brainly.com/question/12539110

#SPJ9

5 0
2 years ago
Set up, but do not evaluate, the integral that represents the length of the curve given by
netineya [11]

Answer:

L = ∫₀²ᵖⁱ √((1 − sin t)² + (1 − cos t)²) dt

Step-by-step explanation:

Arc length of a parametric curve is:

L = ∫ₐᵇ √((dx/dt)² + (dy/dt)²) dt

x = t + cos t, dx/dt = 1 − sin t

y = t − sin t, dy/dt = 1 − cos t

L = ∫₀²ᵖⁱ √((1 − sin t)² + (1 − cos t)²) dt

Or, if you wish to simplify:

L = ∫₀²ᵖⁱ √(1 − 2 sin t + sin²t + 1 − 2 cos t + cos²t) dt

L = ∫₀²ᵖⁱ √(3 − 2 sin t − 2 cos t) dt

7 0
4 years ago
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