Answer:
27m^6n^12
Step-by-step explanation:
(3)^3 = 27
m^2^3 = m^6
n^4^3 = n^12
The cross section of the satellite dish is an illustration of a quadratic function
The quadratic function that models the cross-section is y = 1/6(x^2 - 9)
<h3>How to determie the equation of the cross-section?</h3>
The given parameters are:
Width = 6 feet
Depth = 1.5 feet
Express the width the sum of two equal numbers
Width = 3 + 3
The above means that, the equation of the cross section passes through the x-axis at:
x = -3 and 3
So, we have:
y = a(x - 3) * (x + 3)
Express as the difference of two squares
y = a(x^2 - 9)
The depth is 1.5.
This is represented as: (x,y) =(0,-1.5)
So, we have:
-1.5 = a(0^2 - 9)
Evaluate the exponent
-1.5 = -9a
Divide both sides by -9
a = 1/6
Substitute 1/6 for a in y = a(x^2 - 9)
y = 1/6(x^2 - 9)
Hence, the quadratic function that models the cross-section is y = 1/6(x^2 - 9)
Read more about quadratic functions at:
brainly.com/question/1497716
To solve for the missing steps, let's rewrite first the problem.
Given:
In a plane, line m is perpendicular to line t or m⟂t
line n is perpendicular to line t or n⟂t
Required:
Prove that line m and n are parallel lines
Solution:
We know that line t is the transversal of the lines m and n.
With reference to the figure above,
∠ 2 and ∠ 6 are right angles by definition of <u>perpendicular lines</u>. This states that if two lines are perpendicular with each other, they intersect at right angles.
So ∠ 2 ≅ ∠ 6. Since <u>corresponding</u> angles are congruent.
Therefore, line m and line n are parallel lines.
<span>
<em>ANSWERS: perpendicular lines, corresponding</em>
</span>
Answer:
the 3 represent a one thousand
so that means 4.oo9* 1000 = =49
<h3>
Answer: False</h3>
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Explanation:
I'm assuming you meant to type out
(y-2)^2 = y^2-6y+4
This equation is not true for all real numbers because the left hand side expands out like so
(y-2)^2
(y-2)(y-2)
x(y-2) .... let x = y-2
xy-2x
y(x)-2(x)
y(y-2)-2(y-2) ... replace x with y-2
y^2-2y-2y+4
y^2-4y+4
So if the claim was (y-2)^2 = y^2-4y+4, then the claim would be true. However, the right hand side we're given doesn't match up with y^2-4y+4
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Another approach is to pick some y value such as y = 2 to find that
(y-2)^2 = y^2-6y+4
(2-2)^2 = 2^2 - 6(2) + 4 .... plug in y = 2
0^2 = 2^2 - 6(2) + 4
0 = 4 - 6(2) + 4
0 = 4 - 12 + 4
0 = -4
We get a false statement. This is one counterexample showing the given equation is not true for all values of y.
